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2 years ago

7

The dot plot shows the number of hours, to the nearest hour, that a sample of 5th graders and 7th graders spend watching televis

ion each week. What are the mean and median?

2 answers:

Black_prince [1.1K]2 years ago

6 0

Answer:

is the median for both of them .

Step-by-step explanation:

SpyIntel [72]2 years ago

5 0

Answer:

5th grade mean: 4.67

7th grade mean: 3.46

5th grade median: 5

7th grade median: 3.5

Step-by-step explanation:

I did the math :) (also sorry if this is late, I was looking for the answer but no one had it, so I decided to help out other peeps with the same problem)

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Given: AD = BC and BCD = ADC <br> Prove: DE = CE

erastova [34]

Answer:

According to AD=BC So AC=BD

Step-by-step explanation:

AD = BC and angle ADC = angle BCD

we have to prove AC = BD

let's see ∆ADC and ∆BCD

AD = BC [ given ]

angle ADC = angle BCD [ given ]

CD = CD

from S - A - S

∆ADC congruence ∆BCD

3 0

2 years ago

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The owner of a fish market determined that the mean weight for a catfish is 3.2 pounds with a standard deviation of 0.8 pound. A

madam [21]

Answer: The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is 0.596

Step-by-step explanation:

Since the weights of catfish are assumed to be normally distributed,

we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = weights of catfish.

µ = mean weight

σ = standard deviation

From the information given,

µ = 3.2 pounds

σ = 0.8 pound

The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is is expressed as

P(x ≤ 3 ≤ 5.4)

For x = 3

z = (3 - 3.2)/0.8 = - 0.25

Looking at the normal distribution table, the probability corresponding to the z score is 0.401

For x = 5.4

z = (5.4 - 3.2)/0.8 = 2.75

Looking at the normal distribution table, the probability corresponding to the z score is 0.997

Therefore,.

P(x ≤ 3 ≤ 5.4) = 0.997 - 0.401 = 0.596

4 0

2 years ago

Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat

yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

$P(t) = 0.8t^{2} + 6t + 19000$

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

$P(t) = 0.8t^{2} + 6t + 19000$

$0.8t^{2} + 6t + 19000 = 34200$

$0.8t^{2} + 6t - 15200 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$0.8t^{2} + 6t - 15200 = 0$

So $a = 0.8, b = 6, c = -15200$

Then

$\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356$

$t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14$

$t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64$

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0

2 years ago

The population of a parish is growing with an annual percentage rate compounded continuously. The population reaches 1.1 times i

Sauron [17]

Answer:

4.8%

Step-by-step explanation:

The population that grows with an annual percentage rate compounded continuously is given by: H = H° e^rt

Let the population be represented by H

The population reaches 1.1 times its previous size in 2 years.

So when t=2,

H = 1.1 H°

We substitute to obtain:

1.1 H° = H° e^r2

1.1 = e^2r

Take natural log to get:

In 1.1 = 2r

r = In 1.1 /2

r = 0.0477

Therefore the annual percentage rate is 4.8%

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2 years ago

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A building engineer analyzes a concrete column with a circular cross section. The circumference of the column is 18pi meters. Wh

ella [17]

Answer

Circumference(C) of a circle is given by:

$C = 2\pi r$

where r is the radius and value of $\pi = 3.14$

As per the given statement:

A building engineer analyzes a concrete column with a circular cross section.

The circumference of the column is $18 \pi$ meters.

then;

$18 \pi= 2\pi r$

Divide both sides by $2 \pi$ we have;

9 = r

or

r = 9 meters

We have to find the area of the cross section of the column

Area of a circle is given by:

$A = \pi r^2$

then;

$A = \pi \cdot 9^2 = 81 \pi$ meter square.

therefore, the area A of the cross section of the column is $81 \pi$ meter square.

3 0

2 years ago

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