<span>Chunking increases the capacity of short-term memory by recoding information into more meaningful units. When large amounts of information are given, short-term memory usually remembers the first set of unrehearsed information (primacy) or the last set of unrehearsed information (recency), but few things from the middle.</span>
The correct answer to this open question is the following.
Mass media and communications technology can be used to preserve indigenous languages in the Americas in different ways.
According to the<em> graphics</em> attached, we can see that in the Americas, 17% of the languages are lost and 16% are endangered.
This data is critical and concerns not only scholars or historians, but it has to worry all the citizens because part of our history can be erased if indigenous languages disappear.
Mass media can be used to help solve this issue because modern technology has no frontiers. If governments invest in proper technological infrastructure to take modern communications systems to the tribes or far away places where many tribes inhabit, this could be a direct way to rescue those endangered languages. This possibility shows that there are options available. The use of the internet is a great resource, proving that no matter the distance, every member of a society or indigenous tribe can be connected and could take classes on the internet, or listening to news broadcasting systems in their former language, as well as reading publications in their languages.
Answer:
I believe the options are:
A.chemical energy in the bonds of food molecules
B.carbon energy in molecules of carbon dioxide
C.solar energy in the rays of sunlight
D.electrical energy in the form of hydrogen ions
The correct answer is A. Chemical energy in the bonds of food molecules
Explanation:
Glycolysis, Krebs Cycle and electron transport chain are the major steps in cellular respiration. Cellular respiration is the break down of sugars, particularly glucose into energy yielding molecules such as ATP, NADH and FADH2.
C6H12O6 + 6O2 --> 6CO2 + 6H2O + ATP
Answer:
<u>The proportion of women who ran the marathon and had a finishing time less than Kathy's is 66% (rounding to the next whole)</u>
Explanation:
1. Let's review the information given to us to answer the question properly:
μ of finishing time for women = 259 minutes
σ of finishing time for women = 32 minutes
Finishing time for Kathy = 272 minutes
2. What proportion of women who ran the marathon had a finishing time less than Kathy's? Show your work.
Let's calculate the z-score for the finishing time for Kathy, as follows:
z-score = (272 - 259)/32
z-score = 13/32 = 0.41 (rounding to the next hundredth)
Using the z-table, now we can calculate the proportion of women who ran the marathon had a finishing time less than Kathy's:
p (z=0.41) = 0.6591
<u>The proportion of women who ran the marathon and had a finishing time less than Kathy's is 66% (rounding to the next whole)</u>
