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xeze [42]
2 years ago
14

Write a JavaScript program that reads three integers named start, end, and divisor from three text fields. Your program must out

put to a div all the integers between start and end, inclusive, that are evenly divisible by divisor. The output integers must be separated by spaces. For example, if a user entered 17, 30, and 5, your program would output "20 25 30" (without the quotes) because those are the only integers between 17 and 30 (including 17 and 30) that are evenly divisible by 5.

Computers and Technology
1 answer:
12345 [234]2 years ago
8 0

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Write a JavaScript program that reads three integers named start, end, and divisor from three text fields. Your program must output to a div all the integers between start and end, inclusive, that are evenly divisible by divisor. The output integers must be separated by spaces. For example, if a user entered 17, 30, and 5, your program would output "20 25 30" (without the quotes) because those are the only integers between 17 and 30 (including 17 and 30) that are evenly divisible by 5.

DO NOT SUBMIT CODE THAT CONTAINS AN INFINITE LOOP. If you try to submit code that contains an infinite loop, your browser will freeze and will not submit your exam to I-Learn.

If you wish, you may use the following HTML code to begin your program.  

Due to some techincal problems the remaining answer is attached as images!

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Sunny_sXe [5.5K]
If it's MS Word (it probably is), then it's Alt + F7
7 0
2 years ago
Read 2 more answers
2) Complete the get_num_of_characters() function, which returns the number of characters in the user's string. We encourage you
Lilit [14]

Explanation:

Number of characters: 46

String with no whitespace: Theonlythingwehavetofearisfearitself.

########################################################

def get_num_of_characters(inputStr):

   count = 0

   for i in range(0,len(inputStr)):

       count = count + 1

   #count = len(inputStr)

   return count

def output_without_whitespace(inputStr):

   #statement = statement.strip()

   statement2 = ' '

   for i in range(0,len(inputStr)):

        if(inputStr[i] == ' '):

           statement2 = statement2

       else:

           statement2 = statement2 + inputStr[i]

       

   inputStr = inputStr.replace(" ", "")

   return statement2

inputStr = input('Enter a sentence or phrase: ')

print()

print('You entered:', inputStr)

num = get_num_of_characters(inputStr)

print()

print('Number of characters:', num)

print('String with no whitespace:',output_without_whitespace(inputStr))

#if __name__ == '__main__':

   # Think I'm supposed to use this if statement

########################################################

'''ERROR MESSAGE WHEN RUNNING TEST

Unit test

0/1

Tests that get_num_of_characters() returns 46 for "The only thing we have to fear is fear itself."

Your output

Enter a sentence or phrase: Traceback (most recent call last):

 File "zyLabsUnitTestRunner.py", line 4, in <module>

   from zyLabsUnitTest import test_passed

 File "/home/runner/local/unit_test_student_code/zyLabsUnitTest.py", line 1, in <module>

   from main import get_num_of_characters

 File "/home/runner/local/unit_test_student_code/main.py", line 19, in <module>

   inputStr = input('Enter a sentence or phrase: ')

EOFError: EOF when reading a line'''

6 0
2 years ago
Declare a struct named PatientData that contains two integer data members named heightInches and weightPounds. Sample output for
boyakko [2]

Answer:

struct PatientData{

   int heightInches, weightPounds;

};

Explanation:

In order to declare the required struct in the question, you need to type the keyword <em>struct</em>, then the name of the struct - <em>PatientData</em>, <em>opening curly brace</em>, data members - <em>int heightInches, weightPounds;</em>, <em>closing curly brace</em> and <em>a semicolon</em> at the end.

Note that since the object - lunaLovegood, is declared in the main function, we do not need to declare it in the struct. However, if it was not declared in the main, then we would need to write <em>lunaLovegood</em> between the closing curly brace and the semicolon.

8 0
2 years ago
Use the loop invariant (I) to show that the code below correctly computes the product of all elements in an array A of n integer
NeTakaya

Answer:

Given Loop Variant P = a[0], a[1] ... a[i]

It is product of n terms in array

Explanation:

The Basic Step: i = 0, loop invariant p=a[0], it is true because of 'p' initialized as a[0].

Induction Step: Assume that for i = n - 3, loop invariant p is product of a[0], a[1], a[2] .... a[n - 3].

So, after that multiply a[n - 2] with p, i.e P = a[0], a[1], a[2] .... a[n - 3].a[n - 2].

After execution of while loop, loop variant p becomes: P = a[0], a[1], a[2] .... a[n -3].a[n -2].

for the case i = n-2, invariant p is product of a[0], a[1], a[2] .... a[n-3].a[n-2]. It is the product of (n-1) terms. In while loop, incrementing the value of i, so i=n-1

And multiply a[n-1] with p, i.e P = a[0].a[1].a[2].... a[n-2].

a[n-1]. i.e. P=P.a[n-1]

By the assumption for i=n-3 loop invariant is true, therefore for i=n-2 also it is true.

By induction method proved that for all n > = 1 Code will return product of n array elements.

While loop check the condition i < n - 1. therefore the conditional statement is n - i > 1

If i = n , n - i = 0 , it will violate condition of while loop, so, the while loop will terminate at i = n at this time loop invariant P = a[0].a[1].a[2]....a[n-2].a[n-1]

6 0
2 years ago
Which of the following describes an executive information system (EIS)?
rjkz [21]
I think the answer is b

hope this helps :)
3 0
2 years ago
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