Answer:
def leap_year_check(year):
return if int(year) % 4 == 0 and (int(year) % 100 != 0 or int(year) % 400 == 0)
Explanation:
The function is named leap_year_check and takes in an argument which is the year which we wish to determine if it's a new year or not.
int ensures the argument is read as an integer and not a float.
The % obtains the value of the remainder after a division exercise. A remainder of 0 means number is divisible by the quotient and a remainder other wise means it is not divisible by the quotient.
If the conditions is met, that is, (the first condition is true and either the second or Third condition is true)
the function leap_year_check returns a boolean ; true and false if otherwise.
Answer:
The page changes with the recommendation component have NOT been published.
Explanation:
The community builders are generally used to identify different opportunities by utilizing the necessary creativity, analysis and strategies. This will ensure that the objectives are achieved at the end of the day. Based on the problem encountered during the operation, it shows that the necessary page changes were not published.
Answer: It arranges text in a list alphabetically from A to Z.
Explanation: It's always easier and more systematic to arrange alphabetically. With numbers there is the possibility of infinity but not with alphabet which have a defined range.
Answer:
Line of sight and rules of composition
Explanation:
He needs the rules of composition in order to use the line of sight
Answer:
In Python:
num = int(input("Enter number: "))
maxn = num
while num >=0:
if num>maxn:
maxn = num
num = int(input("Enter number: "))
print("Largest: "+str(maxn))
Explanation:
Get input from the user
num = int(input("Enter number: "))
Initialize the largest to the first input
maxn = num
This loop is repeated until a negative input is recorded
while num >=0:
If the current input is greater than the previous largest
if num>maxn:
Set largest to the current input
maxn = num
Get another input from the user
num = int(input("Enter number: "))
Print the largest
print("Largest: "+str(maxn))
