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2 years ago

If PΔERO = 68 units and ΔERO has ER = x units, RO = 2x units, and EO = 3x units, what is the length of EO?

Mathematics

1 answer:

Artist 52 [7]2 years ago

6 0

Answer:

34 units

Step-by-step explanation:

The perimeter of a triangle is given by the sum of the lengths of its three sides.

So if the perimeter is 68 units and the sides measure x, 2x and 3x, we have that:

x + 2x + 3x = 68

6x = 68

x = 68/6 units

Now with the value of x we can find the length of EO:

EO = 3x

EO = 3 * (68/6)

EO = 68/2 = 34 units

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Use Lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint. (If an answer d

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Answer:

The maximum value is 1/27 and the minimum value is 0.

Step-by-step explanation:

Note that the given function is equal to $(xyz)^2$ then it means that it is positive i.e $f(x,y,z)\geq 0$ .

Consider the function $F(x,y,z,\lambda)=x^2y^2z^2-\lambda (x^2+y^2+z^2-1)$

We want that the gradient of this function is equal to zero. That is (the calculations in between are omitted)

$\frac{\partial F}{\partial x} = 2x(y^2z^2 - \lambda)=0$

$\frac{\partial F}{\partial y} = 2y(x^2z^2 - \lambda)=0$

$\frac{\partial F}{\partial z} = 2z(x^2y^2 - \lambda)=0$

$\frac{\partial F}{\partial \lambda} = (x^2+y^2+z^2-1)=0$

Note that the last equation is our restriction. The restriction guarantees us that at least one of the variables is non-zero. We've got 3 options, either 1, 2 or none of them are zero.

If any of them is zero, we have that the value of the original function is 0. We just need to check that there exists a value for lambda.

Suppose that x is zero. Then, from the second and third equation we have that

$-2y\lambda = -2z\lambda$ . If lambda is not zero, then y =z. But, since $-2y\lambda=0$ and lambda is not zero, this implies that x=y=z=0 which is not possible. This proofs that if one of the variables is 0, then lambda is zero. So, having one or two variables equal to zero are feasible solutions for the problem.

Suppose that only x is zero, then we have the solution set $y^2+z^2=1$ .

If both x,y are zero, then we have the solution set $z^2=1$ . We can find the different solution sets by choosing the variables that are set to zero.

NOw, suppose that none of the variables are zero.

From the first and second equation we have that

$\lambda = y^2z^2 = x^2z^2$ which implies $x^2=y^2$

Also, from the first and third equation we have that

$\lambda = y^2z^2 = x^2y^2$ which implies $x^2=z^2$

So, in this case, replacing this in the restriction we have $3z^2=1$ , which gives as another solution set. On this set, we have $x^2=y^2=z^2=\frac{1}{3}$ . Over this solution set, we have that the value of our function is $\frac{1}{3^3}= \frac{1}{27}$

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2 years ago

Roger is paid $50 to sell videos of a play to an audience after the play is

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Answer:

0 ≤ v ≤ 230

Step-by-step explanation:

The function E(v)=50+2v models the amount of money Roger earns by selling v videos.

Roger is paid $50 to sell videos of a play to an audience after the play is performed. He also receives $2 for each video he sells.

Now, it is given that the play's audience consist of 230 people and each audience member buys no more than 1 video.

Therefore, the domain of the function will be given by

0 ≤ v ≤ 230

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2 years ago

Benito and Tyler are painting opposite sides of the same fence. Tyler has already painted 19 ½ feet of his side of the fence whe

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Answer:

Part A: The time it will take for both of them to painted equal number of feet is 4.875 minutes

The number of feet Benito will have painted when the two sides have equal length is 73.125 feet

Part B: It is not true that Tyler will finish painting his side of the fence before Benito finishes painting his

Part C: Time to rest is 1.864 minutes

Step-by-step explanation:

The given information are;

The length of fence Tyler already painted when Benito started = 19 ¹/₂ feet

Benito paints 15 feet/minute

Tyler paints 11 feet/minute

Length of fence = 150 feet

Part A:

The time it will take for both of them to painted equal number of feet is given as follows;

11×t + 19.5 = 15×t

4×t = 19.5

t = 19.5/4= 4.875 minutes

The time it will take for both of them to painted equal number of feet = 4.875 minutes

The length Benito will have painted when the two sides have equal length = 15 × 4.875 = 73.125 feet

Part B: The time it will take Tyler to finish painting his side of the fence is given as follows;

11 × t + 19.5 = 150

t = (150 - 19.5)/11 ≈ 11.864 minutes

While the time it will take Benito to finish painting his side of the fence is given as follows;

15 × t = 150

t = 150/15 ≈ 10 minutes

Therefore it is not true that Tyler will finish painting his side of the fence before Benito finishes painting his

Part C: Given that Benito finishes before Tyler, the length of time Benito gets to rest is given as follows;

Time to rest = Time Tyler takes to finish - Time Benito takes to finish

Time to rest = 11.864 - 10 = 1.864 minutes.

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