answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ASHA 777 [7]
2 years ago
14

Steve wants to become a successful graphic design entrepreneur. Which entrepreneurial approach will help him succeed? A. working

as a graphics artist B. working as an animator C. being employed as a web developer D. employing or hiring designers for work
Computers and Technology
1 answer:
xxMikexx [17]2 years ago
5 0

Answer:

Option(D) is the correct answer to the given question .

Explanation:

The  main objective of graphic design entrepreneur is to design the animation such as company logos, booklets, product labeling ,etc .The graphic designers are also operated independently that is it designing the products for the business customers, marketing firms, newspapers ,public affairs firms and etc.

  • With the help of hiring designers for work  then the steve wants to be a good graphic design businessman and get success in life .
  • All the other option are not correct for the design for graphics that's why these are incorrect option .
You might be interested in
9.6 Code Practice: Question 1
worty [1.4K]

Answer:

  1. import java.util.Random;
  2. import java.util.Arrays;
  3. public class Main {
  4.    public static void main(String[] args) {
  5.        int n = 10;
  6.        int [] myArray = new int[n];
  7.        buildArray(myArray, n);
  8.        System.out.println(Arrays.toString(myArray));
  9.    }
  10.    public static void buildArray(int[] arr, int n){
  11.        for(int i=0; i < arr.length; i++){
  12.            Random rand = new Random();
  13.            arr[i] = rand.nextInt(90) +10;
  14.        }
  15.    }
  16. }

Explanation:

Firstly, create a method buildArray that take two inputs, an array and an array size (Line 12). In the method, use random nextInt method to repeatedly generate a two digit random number within a for loop that will loop over array size number of times (Line 13-15). The expression rand.nextInt(90) + 10 will generate digits between 10 - 99.

In the main program, call the build array method by using an array and array size as input arguments (Line 8). At last, print the array after calling the buildArray method (Line 9).

8 0
2 years ago
Which of the following is NOT a method in which a macro can be run?
liubo4ka [24]
C....................
7 0
2 years ago
Write a copy assignment operator for CarCounter that assigns objToCopy.carCount to the new objects's carCount, then returns *thi
ollegr [7]

Answer:

Here is the copy assignment operator for CarCounter:

CarCounter& CarCounter::operator=(const CarCounter& objToCopy) {

carCount = objToCopy.carCount;

return *this;  }

The syntax for copy assignment operator is:

ClassName& ClassName :: operator= ( ClassName& object_name)

In the above chunk of code class name Is CarCounter and object name is objToCopy.

Assignment operator = is called which assigns objToCopy.carCount to the new objects's carCount.

This operator basically is called when an object which is already initialized is assigned a new value from another current object.

Then return *this returns the reference to the calling object

Explanation:

The complete program is:

#include <iostream>  //to use input output functions

using namespace std;   //to access objects like cin cout

class CarCounter {  //class name

public:  // public member functions of class CarCounter

CarCounter();  //constructor of CarCounter

CarCounter& operator=(const CarCounter& objToCopy);  //copy assignment operator for CarCounter

void SetCarCount(const int setVal) {  //mutator method to set the car count value

carCount = setVal;  } //set carCount so setVal

int GetCarCount() const {  //accessor method to get carCount

return carCount;  }  

private:  //private data member of class

int carCount;  };    // private data field of CarCounter

CarCounter::CarCounter() {  //constructor

carCount = 0;  //intializes the value of carCount in constructor

return; }  

// FIXME write copy assignment operator  

CarCounter& CarCounter::operator=(const CarCounter& objToCopy){

/* copy assignment operator for CarCounter that assigns objToCopy.carCount to the new objects's carCount, then returns *this */

carCount = objToCopy.carCount;

return *this;}  

int main() {  //start of main() function

CarCounter frontParkingLot;  // creates CarCounter object

CarCounter backParkingLot;   // creates CarCounter object

frontParkingLot.SetCarCount(12);  // calls SetCarCount method using object frontParkingLot to set the value of carCount to 12

backParkingLot = frontParkingLot;  //assigns value of frontParkingLot to backParkingLot

cout << "Cars counted: " << backParkingLot.GetCarCount();  //calls accessor GetCarCount method to get the value of carCount and display it in output

return 0;  }

The output of this program is:

Cars counted = 12

3 0
2 years ago
What conclusion can be made about the state of the program when the while loop terminates? Assume answer is a declared and initi
stellarik [79]

<u>Answer:</u>

<em>1. The loop will run unless the value of answer equals to Capital N.</em> The method equals is “case-sensitive” that is lower case letter and upper case letters are considered different. That “a” and “A” means the same to us, but for the method equals it is different and equals method will return false if the case is not matching.

<em>2. a (int)(Math.random() * (upper − lower) ) + lower </em>

Since we need to consider the lower limit value together to get the desired results we need to add the value of lower limit to the multiplied answer.

<em>3. b while(userGuess != secretNumber || userGuess >= lowerLimit && userGuess <= upperLimit)</em>

Here the program is required to check the while loop and exit when user guess the number or we can say the loop should continue until the user guess the number, so that is why we have taken <em>userGuess!=secretNumber. </em>Next the loop should be exited if it is not within the range or we can say that the loop should run only if the guessed number is within the upper and lower limit.<em> That is why we have opted for the condition userGues>=lowerlimit && userGuess<=upperlimit.</em> Why we have taken && as the operator is that, it’s a range of values so && operator best suit for this kind of logical condition.

3 0
2 years ago
Which fact does lean green eco machines present to show that electric cars are not perfect
Yuri [45]

Answer: HOPE THIS HELPED YOU! :D ;)

Eco cars are still too expensive for most car buyers

Explanation:

5 0
2 years ago
Read 2 more answers
Other questions:
  • What is a typical grace period for a credit card...
    15·2 answers
  • Characteristics of a LAN include _____. can be connected to the Internet covers the most area of all networks does not have to b
    5·1 answer
  • In Python, what kind of error is returned by the following code? (e.g. NameError, ValueError, IOError, etc.) def my_func(n1, n2)
    8·1 answer
  • You complete your database, and the company begins using it. Shortly afterwards, two GearUp buyers, Cora and Owen, work together
    9·1 answer
  • Instructions:
    14·1 answer
  • Suppose that, when you arrive at the sale site for $50 Apple laptops (described in the text) at 1:45 A.M., you find more than 2,
    8·1 answer
  • James has created some artwork portraying life on a different planet. He wants to show a world where everything is beautiful and
    7·1 answer
  • Describe the indicators and hazards of a metal deck roof fire in an unprotected steel joist warehouse as well as the techniques
    6·1 answer
  • You work for a car rental agency and want to determine what characteristics are shared among your most loyal customers. To do th
    10·1 answer
  • What temperature is most commonly used in autoclaves to sterilize growth media and other devices prior to experimentation
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!