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adelina 88 [10]
2 years ago
8

Let $\overline{XY}$ be a tangent to a circle, and let $\overline{XBA}$ be a secant of the circle, as shown below. If $AX = 15$ a

nd $XY = 9$, then what is $AB$?
Mathematics
1 answer:
KiRa [710]2 years ago
8 0

Answer:

AB=5.4 units

Step-by-step explanation:

We using the theorem of intersecting tangent and secant to solve this.

By this theorem:

XY^2=XB \times AX\\9^2=15(15-XB)\\81=225-15XB\\15XB=144\\XB=9.6\\$Therefore:\\AB=AX-XB\\AB=15-9.6\\AB=5.4$ units

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