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adelina 88 [10]
2 years ago
8

Let $\overline{XY}$ be a tangent to a circle, and let $\overline{XBA}$ be a secant of the circle, as shown below. If $AX = 15$ a

nd $XY = 9$, then what is $AB$?
Mathematics
1 answer:
KiRa [710]2 years ago
8 0

Answer:

AB=5.4 units

Step-by-step explanation:

We using the theorem of intersecting tangent and secant to solve this.

By this theorem:

XY^2=XB \times AX\\9^2=15(15-XB)\\81=225-15XB\\15XB=144\\XB=9.6\\$Therefore:\\AB=AX-XB\\AB=15-9.6\\AB=5.4$ units

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Which statements about the graph of the function f(x) = 2x^2– x – 6 are true? Select two options.
Alekssandra [29.7K]

Answer:

Step-by-step explanation:

Please, share the answer options next time.

1)  f(x) = 2x^2– x – 6 is a quadratic function.  

2) The coefficients of this polynomial are a = 2, b = -1 and c = -6

2)  Its graph opens up.

3)  The x-value of the axis of symmetry and the vertex is x = -b / (2a), which here comes out to x = -(-1) / [2(2)], or x = 1/4

4) the y coordinate of the vertex is f(1/4), or -6 1/8

5) The vertex is at (1/4, -6 1/8)

6)  The y-intercept is at f(0):  2(0)^2 - 0 - 6 = -6  =>  (0, -6)

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2 years ago
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A carton of milk has spilled on a tile floor. The milk flow can be expressed with the function m(t) = 9t, where t represents tim
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Part A)     means that we have to find a composition of functions A and m
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Emily invests $5,000 in an
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Answer:

50 years

Step-by-step explanation:

use the simple interest formula :

PRT/100

P is the principle (5000)

R is the rate of interest (4)

T is the time taken (x- unknown)

the amount at the end is double the amount invested  = 5000*2 = 10000

(5000*4 * x )/100 = 10000

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Mattel Corporation produces a remote-controlled car that requires three AA batteries. The mean life of these batteries in this p
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Answer:

0.0406, 0.8284,0.7887

Step-by-step explanation:

Given that Mattel Corporation produces a remote-controlled car that requires three AA batteries

X is N(34, 5.5)

Hence sample size of 25 would follow a t distribution with df = 24

This is because sample size <30

t distribution with df 24 would be bell shaped symmetrical about the mean and unimodal.

Std error of sample mean = std dev /sqrt n=\frac{5.5}{5} \\=1.1

Prob (X>36) = P(t>\frac{36-34}{1.1} ) = P(t>1.82)\\= 0.04063

i.e nearly 4.1% of the sample would have a mean useful life of more than 36 hours

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Proportion between 33.5 and 36 hours

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6 0
2 years ago
6.In a sample of 131 women with cosmetic dermatitis from using eye shadow, 12 were diagnosed with a nickel allergy. In a sample
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Answer:

a) 0.0916 - 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.0422

0.0916 + 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.1410

So then we can conclude that the true proportion of women with cosmetic dermatitis from using eye shadow at 95% of confidence is between (0.0422 and 0.1410)

b) \hat p = \frac{25}{250}= 0.1

0.1 - 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.0628

0.1 + 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.1372

So then we can conclude that the true proportion of women with cosmetic dermatitis from using mascara at 95% of confidence is between (0.0628 and 0.1372)

c) For this case we see that both confidence intervals contains the value of 0.12 so then we can't conclude that only one group is referenced at the significance level of 0.05 used.

Step-by-step explanation:

Part a

The estimated proportion of women with cosmetic dermatitis from using eye shadow is given by:

\hat p =\frac{12}{131}= 0.0916

The confidence  interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the proportion is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Replacing we got:

0.0916 - 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.0422

0.0916 + 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.1410

So then we can conclude that the true proportion of women with cosmetic dermatitis from using eye shadow at 95% of confidence is between (0.0422 and 0.1410)

Part b: A 95% confidence interval for the women with cosmetic dermatitis from using mascara

\hat p = \frac{25}{250}= 0.1

0.1 - 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.0628

0.1 + 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.1372

So then we can conclude that the true proportion of women with cosmetic dermatitis from using mascara at 95% of confidence is between (0.0628 and 0.1372)

Part c: Suppose you are informed that the true proportion with a nickel allergy for one of the two groups (eye shadow or mascara) is .12. Can you determine which group is referenced? Explain.

For this case we see that both confidence intervals contains the value of 0.12 so then we can't conclude that only one group is referenced at the significance level of 0.05 used.

7 0
2 years ago
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