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elena55 [62]
2 years ago
15

Find the interquartile range (IQR) of the data in the dot plot below. chocolate chips 0 0 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10

10. Number of chocolate chips. Chocolate chips in different cookies in a package

Mathematics
1 answer:
Brums [2.3K]2 years ago
3 0

*The dot plot is shown in the attachment below

Answer:

2

Step-by-step explanation:

Interquartile range is the difference between the upper median (Q3) and the lower median (Q1).

First, let's write out each value given in the data. Each dot represents a data point.

We have:

2, 3, 3, 4, 4, 4, 4, 5, 5, 6, 7

=>Find the median:

Our median is the middle value. The middle value is the 6th value = 4

==>Upper median Q3) = the middle value of the set of data we have from the median to our far right.

2, 3, 3, 4, 4, |4,| 4, 5, [5], 6, 7

Our upper median = 5

==>Lower median(Q1) = the middle value of the data set we have from our median to our far left.

2, 3, [3], 4, 4, |4,| 4, 5, 5, 6, 7

Lower median = 3

==>Interquartile range = Q3 - Q1 = 5-3 = 2

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We can use the Pascal's Triangle to solve this problem. This pascal's triangle is shown in the figure below. To build the triangle, begin with the number 1 at the top, then continue placing numbers below it in a triangular pattern. In this way, each number are the numbers directly above added together. So, the expression:

(x+y)^{10}

Can be extended as follows, for n = 10:

(x+y)^{10}=x^{10}+10x^{9}y+45x^{8}y^2+120x^{7}y^3+210x^{6}y^4+252x^{5}y^5+210x^{4}y^6+120x^{3}y^7+45x^{2}y^8+10xy^9+y^{10}

So, the 8th term of the binomial expansion is:

120x^{3}y^7

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2 years ago
Which of the following statements are true of a least - squares regression equation? *
zaharov [31]
Where’s is your problem?
7 0
2 years ago
The quotient of 38 times a number and -4
nikdorinn [45]

Answer:

140y

Step-by-step explanation:

35 times a number times -4 is 35×y×(-4) which is -140y

4 0
1 year ago
Amir drove from Jerusalem down to the lowest place on Earth, the Dead Sea, descending at a rate of 12 meters per minute. He was
SSSSS [86.1K]
<h2>Answer:</h2>

First of all let's write the slope-intercept form of the equation of a line, which is:

y=mx+b \\ \\ Where: \\ \\ m: \ slope \\ \\ b: \ y-intercept

So we just need to find m \ and \ b to solve this problem.

Moreover, this problem tells us that Amir drove from Jerusalem down to the lowest place on Earth, the Dead Sea, descending at a rate of 12 meters per minute. So this rate is the slope of the line, that is:

m=-12

Negative slope because Amir is descending. So:

y=-12x+b

To find b, we need to use the information that tells us that he was at sea level after 30 minutes of driving, so this can be written as the point (30,0). Therefore, substituting this point into our equation:

y=-12x+b \\ \\ 0=-12(30)+b \\ \\ 0=-360+b \\ \\ \therefore b=360

Finally, the equation of Amir's altitude relative to sea level (in meters) and time (in minutes) is:

\boxed{y=-12x+360}

Whose graph is shown bellow.

6 0
2 years ago
Read 2 more answers
Suppose two different methods are available for eye surgery. The probability that the eye has not recovered in a month is 0.002
umka21 [38]

Answer:

0.4007

Step-by-step explanation:

Let's define the following events:

A: method A is used

B: method B is used

NR: the eye has not recovered in a month

R: the eye is recovered in a month

The probability that the eye has not recovered in a month is 0.002 if method A is used, i.e., P(NR|A) = 0.002, so P(R|A) = 0.998.

When method B is used, the probability that the eye has not recovered in a month is 0.005, i.e., P(NR|B) = 0.005, so P(R|B) = 0.995.

40% of eye surgeries are done with method A, i.e., P(A) = 0.4

60% of eye surgeries are done with method B, i.e., P(B) = 0.6

If an eye is recovered in a month after surgery is done in the hospital, what is the probability that method A was performed? We are looking for P(A|R), then, by Bayes' Formula

P(A|R) = P(R|A)P(A)/(P(R|A)P(A) + P(R|B)P(B)) = 0.998*0.4/(0.998*0.4 + 0.995*0.6) = 0.4007

4 0
2 years ago
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