The proof that ΔACB ≅ ΔECD is shown. Given: AE and DB bisect each other at C. Prove: ΔACB ≅ ΔECD Triangles A B C and C D E share
2 answers:
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1. you have to figure out what 3/4 of Ella's time is.
(You find that out by multiplying 5x1. Then add 3.)
2. Convert the fractions into decimals. (This will help make it easier when dividing.)
3. Next you are going to divide 1.6 by .75
4. Now multiple 2.13 by 5.
Answer is 10
(You find that out by multiplying 5x1. Then add 3.)
2. Convert the fractions into decimals. (This will help make it easier when dividing.)
3. Next you are going to divide 1.6 by .75
4. Now multiple 2.13 by 5.
Answer is 10
Answer:
C. Those who have a car tend to have a cell phone.
Step-by-step explanation:
The relative frequency for a data set n is calculated by dividing each frequency by n.
We have a table that relates the use of cars and cell phones.
First, we take from the table the population that has a car.
Then, of the students who have a car, 12 have a cell phone and 6 do not have a cell phone.
Then we calculate the relative frequencies for those who have a cell phone and those who do not.
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Relative frequency Students with car n = 18.
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C<em>ell phone No cell phone Total n</em>
12/18 6/18 18
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Relative frequency Students with car n = 18.
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C<em>ell phone No cell phone Total n</em>
0.666 0.333 18
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Most students who have a car also have a cell phone.
Now we calculate the relative frequency for students who do not have a car.
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Relative frequency Students without a car n = 7
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<em>Cell phone No cell phone Total n</em>
2/7 5/7 7
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Relative frequency Students without a car n = 7
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<em>Cell phone</em> <em> No</em> <em>cell phone Total n</em>
0.286 0.714 7
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Most students who do not have a car do not have a cell phone either.
<em>Then these data suggest that. Those who have a car tend to have a cell phone.</em>
Option C