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k0ka [10]
2 years ago
8

A family dines in a popular franchise restaurant. At the end of the meal, they decide to leave their server a monetary tip that

is equal to 20% of the total bill amount, $60.50. How much will the family leave their server as a tip?
Mathematics
1 answer:
Maurinko [17]2 years ago
7 0

Answer:

$12.10

Step-by-step explanation:

First, you have to set up a proportion to find what 20% of $60.50, or 60.5, is. On one side of the proportion you have 20/100 to represent the percent, anytime you have a percent it will always go over 100. On the other side you'll have x/60.5 because you are trying to find a value out of 60.5. This gives you the proportion 20/100=x/60.5. In order to solve this you have to cross multiply using the equation 20(60.5)=100x. First, you multiply to get 1210=100x, then divide both sides by 100 to get 12.1=x. In order for this to represent money, we add a zero on the end. This means that 20% of $60.50 is $12.10, so $12.10 is the tip.

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In the 2000 presidential election, three candidates split the vote as follows:
Lera25 [3.4K]

Answer:

c 23 and 0.46 are statistics and 0.484 is a  parameter

True. For this case the value 0.46 represent t statistic since from the sample obtained we can calculate the sample proportion of people who voted for Gore like this:

\hat p_{Gore]=\frac{X}{n}=\frac{23}{50}=0.46

Where X represent the people with the characteristic desired in the random sample selected.

So then we can say that 23 and 0.46 represent statistics since comes from the sample. And the value 0.484 is obtained from the population so then represent a parameter.  

Step-by-step explanation:

Previous concepts

A parameter is any "numerical quantity that characterizes a given population or some aspect of it". For this case we are interested on proportions and we denote the population proportion by p

A statistic is "used to estimate the value of a population parameter". In other words is just an estimation of the population parameter of interest. Four our case the sample proportion denoted by \hat p represent the statistic for this case.

Solution for the problem

a 0.46 and 0.484 are statistics

False. 0.484 is not an statistic since it's the outcome from the original population and would represent the parameter "proportion of people who vote for Gore"

b 50 and 23 are statistics and 0.484 is a  parameter

False. The sample size is not an statistic is just a value selected in order to calculate the statistic.

c 23 and 0.46 are statistics and 0.484 is a  parameter

True. For this case the value 0.46 represent t statistic since from the sample obtained we can calculate the sample proportion of people who voted for Gore like this:

\hat p_{Gore]=\frac{X}{n}=\frac{23}{50}=0.46

Where X represent the people with the characteristic desired in the random sample selected.

So then we can say that 23 and 0.46 represent statistics since comes from the sample. And the value 0.484 is obtained from the population so then represent a parameter.  

6 0
2 years ago
Zane and Matt are both keen runners. Zane takes 4 minutes to jog around a running track and Matt takes 5 minutes. They start at
Sergio [31]
I believe that the correct answer to this question is B. because matt took more than 5 minutes .
3 0
2 years ago
Two components of a minicomputer have the following joint pdf for their useful lifetimes X and Y: f(x, y) = xe−x(1 + y) x ≥ 0 an
Yuri [45]

Answer:

For the given explanation we see that two life times are not independent

Step-by-step explanation:

probability for X (for x≥ 0)

\int\limits^\infty_0 {xe^-^x^(^1^+^y^)} \, dy

-e^-^x\int\limits^\infty_0 {de^-^x^y} \,

e⁻ˣ

Probability for X exceed 3

= \int\limits^\infty_3 {f(x)dx

= \int\limits^\infty_3 {e^-^3 dx

= e^-^3

probabilty for y≥ 0 is

\int\limits^\infty_0 {xe^-^x^(^1^+^y^)} \, dx \\

\int\limits^\infty_0{-x/1+yd(e^-^x^(^1^+^y^))} \, =1/(1+y)² \\

3 0
2 years ago
8.1.3 A random sample has been taken from a normal distribution and the following confidence intervals constructed using the sam
crimeas [40]

Answer:

a) The value of the sample mean is 50

b) (38.02, 61.98) is the 95% as it covers more values than the other.

Step-by-step explanation:

a) Upper and lower values for the confidence intervals are at the same distance from the mean, as they represent an upper and lower limit for the value, and the most probable value is the one in the middle, which, in a normal distribution is the mean.

As they derive from the same data, both pairs of values should give us the same mean:

\mbox {mean}=\frac{\mbox{upper value+lower value}}{\mbox{2} }\\\mbox {mean from the first set}=\frac{38.02+61.98}{2}=50 \\\mbox {mean from the first set}=\frac{39.95+60.05}{2}=50

b) The percentage of the confidence interval tells us which is the area below the bell curve (of the normal distribution) between the limits given.

One could give a value with a 100% CI, but limits should be minus and plus infinity, and as the interval gets smaller, less values are covered (less area), and less certain we are about our value being inside the interval.

Then, we can say that the widest interval must be the 95% CI, i.e. (38.02, 61.98).

8 0
2 years ago
Which of these statements best describes the relation shown in Item 1?
Oksi-84 [34.3K]

Answer:

The relation is 'a function that is one-to-many'.

Step-by-step explanation:

From the table, we can see that element 10 i.e. y=10 in the range, corresponds to two elements i.e. x=-5, and x=5 in the domain.

In other words, the given table represents the many-to-one function as an element of the range y = 10 corresponds to more than one element in the domain.

Therefore, the relation is 'a function that is one-to-many'.

3 0
2 years ago
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