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Alchen [17]
2 years ago
11

Which of the following is true? a. Pseudocode is used to describe an algorithm. b. Pseudocode is not an actual computer programm

ing language. c. Pseudocode is used to describe executable statements that will eventually be translated by the programmer into a program. d. All of the above.
Computers and Technology
1 answer:
Leviafan [203]2 years ago
4 0

Answer:

Correct answer is:

d. All of the above

Explanation:

First of all, let us learn about a pseudo code:

<u>Pseudo code</u>: It is an implementation of any algorithm written with the help of annotations and text using in simple English. (So, point a. is true)

It is written in English so its syntax is not like any actual programming language. (So, point b. is true)

Pseudo code describes what each line of pseudo code will do so the code writing becomes easier simply by translating the pseudo code to actual programming language syntax i.e. point c. is true.

Hence, point "<em>d. All of the above</em>" is true.

Advantages of Pseudo code :

  • It makes the readability of the program idea/approach better.
  • Code writing becomes easier for the programmer.

Correct answer is:

d. All of the above

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Answer:

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Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255
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Answer:

Follows are the code to this question:

#include <iostream>//defining a header file

using namespace std; //using namespace

int main() //defining main method

{

int red,green,blue,s; //defining integer variable

cout<<"Enter value: \n ";//print message

cin>>red>>green>>blue; //input value

if(red<green && red<blue)//defining if block that checks red value

s=red;//store red variable value to s variable

else if(green<blue)//defining else if block that checks green value less then blue

s=green;//store green variable value in s variable

else//defining else block

s=blue; //store blue variable value in s variable

//calculating red, green, blue value

red=red-s;//store red value

green=green-s;//store green value

blue=blue-s;//store blue value

cout<<red<<" "<<green<<" "<<blue;

}

Output:

Enter value:

130  

50

130

80 0 80

Explanation:

In the above code, inside the Main method, four integer variable "red, green, blue, and s" is defined, in which "red, green, and blue" is used for input the value from the user end.

  • In the next step, a conditional statement is used, that checks the red variable value, if the condition is true, it will store its value in the "s" variable, otherwise, it will go to else if block.
  • In this block, the green variable checks its value less than then blue variable value, if the condition is true, it will store the green value in the "s" variable, otherwise, it will goto else block.
  • In this block, it will store the blue variable value in the "s" variable, and subtract the value of "red, green, and blue" value from "s" and store its value, and at the last, it will print its value.    
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Answer:

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Explanation:

The explanation is provided in the attached document.

The screenshot of the complete code along with its output is attached.

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