Answer:
The correct answer is:
a. M54.6, C79.51, C80.1
Explanation:
- M54.6 Pain in thoracic spine. It is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.
- C79.51: Secondary malignant neoplasm of bone, it is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes.
- G89. 3 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM G89.
Malignant neoplasm of anus, unspecified
Neoplasm related pain (acute) (chronic)
Pain in thoracic spine. M54. 6 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.
Malignant (primary) neoplasm, unspecified
- C80. 1 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM C80.
Answer:
The answer is "Using the DoD 5220.22-M method and Degauss media with a magnet".
Explanation:
The "DoD Standard" is a term used during the data sanitizing industry and refers to DoD 5220.22-M. The simplest ways are being used to help eliminate the previously stored data, by deleting hard disc storage facilities with the same data wherever that used a sequence of all zeros.
The sparging eliminates statistics to entirely delete the gravitational flux from electronic media. Hard drives as well as other data storage devices, for example, computer tapes, retain magnetic data. It could no longer be seen as storage after a disk is degaussed.
Answer:
Steps 2 and 3 needs to be switched.
Explanation:
e2020
Answer:
The program in Python is as follows:
n = int(input("Enter an integer: "))
if n < 0:
n = 0
print("Sequence:",end=" ")
for i in range(n,-1,-1):
if i%2 == 0:
print(i,end = " ")
Explanation:
This gets input for n
n = int(input("Enter an integer: "))
This sets n to 0 if n is negative
<em>if n < 0:</em>
<em> n = 0</em>
This prints the string "Sequence"
print("Sequence:",end=" ")
This iterates from n to 0
for i in range(n,-1,-1):
This check if current iteration value is even
if i%2 == 0:
If yes, the number is printed
print(i,end = " ")
Answer:
There is a need for some people to see the total transparency of the records that are meant to be shared with a select group of people. There are certain things that can be done for this. The first one is that the sharing rules should be checked. To whom are the details shared with. The next one is the filters that are used.
These can be reported and changed accordingly. Lastly, the whole organization’s defaults can be checked. This is something that can be done when the previous methods that were done did not work that well. Once some changes are done, the people can check if they already work and if the records can be viewed.
Explanation:
