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Ad libitum [116K]
2 years ago
4

what is the midpoint of the segment shown below (2 2) (3 5) a. (5/2, 7/2) b. (5, 7) c. (5/2, 7) d. (5, 7/2)

Mathematics
1 answer:
Ahat [919]2 years ago
6 0

Answer:

<h2>( \frac{5}{2}  \: , \frac{7}{2} )</h2>

Option A is the correct option.

Step-by-step explanation:

Let the points be A and B

A ( 2 , 2 ) ------> ( x1 , y1 )

B ( 3 , 5 ) -------> ( x2 , y2)

Now, let's find the mid-point :

Midpoint = (\frac{x1 + x2}{2}  \:,  \frac{y1 + y2}{2} )

plug the values

= ( \frac{2 + 3}{2}  \: , \frac{2 + 5}{2} )

Calculate the sum

= \: ( \frac{5}{2}  \:,  \frac{7}{2} )

Hope this helps..

Best regards!!

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Answer:

The domain of the function is the interval [0,2.23]

see the explanation

Step-by-step explanation:

Let

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h(t) ----> the height of the laptop in units

we have

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we know that

When the laptop hits the ground, the value of h(t) is equal to zero

so

For h(t)=0

-16t^{2}+28t+17=0

Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

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x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^{2}+28t+17=0

so

a=-16\\b=28\\c=17

substitute in the formula

x=\frac{-28(+/-)\sqrt{28^{2}-4(-16)(17)}} {2(-16)}

x=\frac{-28(+/-)\sqrt{1,872}} {-32}

x=\frac{-28(+/-)12\sqrt{13}} {-32}

x_1=\frac{-28(+)12\sqrt{13}} {-32}=-0.477

x_1=\frac{28(-)12\sqrt{13}} {32}=-0.477  ---> is not a solution

x_2=\frac{-28(-)12\sqrt{13}} {-32}

x_2=\frac{28(+)12\sqrt{13}} {32}=2.23\ sec

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The domain of the function is the interval [0,2.23]

All real numbers greater than or equal to 0 seconds and less than or equal to 2.23 seconds

0\ sec \leq x \leq 2.23\ sec

5 0
2 years ago
Find H.C.F. and L.C.M. of x3-y3, x2-y2 and (x-y) ?​
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Answer:

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2)x²-y² =(x-y)(x+y)

3)x-y = (x-y)

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Step-by-step explanation:

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Answer:

see the explanation

The graph in the attached figure

Step-by-step explanation:

<u><em>The correct question is</em></u>

Explain what the slope and intercept mean in each situation.

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see the attached figure to better understand the problem

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In this context

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so

The value of the perimeter is 0 when the value of side length is 0

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