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horrorfan [7]
2 years ago
6

The table below shows data from a survey about the amount of time students spend doing homework each week. The students were in

either college or high school:
High Low Q1 Q3 IQR Median Mean σ
College 20 6 8 18 10 14 13.3 5.2
High School 20 3 5.5 16 10.5 11 11 5.4


Which of the choices below best describes how to measure the spread of these data?
(Hint: Use the minimum and maximum values to check for outliers.)
Both spreads are best described by the IQR.
Both spreads are best described by the standard deviation.
The college spread is best described by the IQR. The high school spread is best described by the standard deviation.
The college spread is best described by the standard deviation. The high school spread is best described by the IQR.
Mathematics
1 answer:
nadezda [96]2 years ago
4 0

Answer:

The correct option is;

Both spreads are best described by the standard deviation

Step-by-step explanation:

The given information are;

,                                    College                       High School

High,                              20                               20

Low,                                6                                 3

Q₁,                                   8                                 5.5

Q₃,                                  18                                16

IQR,                                 10                                10.5

Median,                           14                                11

Mean,                              13.3                             11

σ,                                      5.2                             5.4

Checking for outliers, we have

College

Q₁ - 1.5×IQR gives 8 - 1.5×10 = -7

Q₃ + 1.5×IQR gives 18 + 1.5×10 = 33

For high school

Q₁ - 1.5×IQR gives 5.5 - 1.5×10.5 = -10.25

Q₃ + 1.5×IQR gives 16 + 1.5×10.5 = 31.75

Therefore, there are no outliers and the data is representative of the population

From the data, for the college students, it is observed that the difference between the mean, 13.3 and Q₁, 8, and between Q₃, 18 and the mean,13.3 is approximately the standard deviation, σ, 5.2

The difference between the low and the high is also approximately 3 standard deviations

Therefore the college spread is best described by the standard deviation

Similarly for the high school students, the IQR is approximately two standard deviations, the  difference between the mean, 11 and Q₁, 5.5, and between Q₃, 16 and the mean,11 is approximately the standard deviation, σ, 5.4

Therefore the high school spread is also best described by the standard deviation.

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2 (x + 1) - 3 cuando x = 6​
katen-ka-za [31]

Answer:

11

Step-by-step explanation:

6+1=7

7x2=14

14-3=11

espero que esto ayude

3 0
2 years ago
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A trip to Portland, Oregon, from Boston will take 7 3/4 hours. Assuming we are two-thirds of the way there, how much longer in h
schepotkina [342]
First turn 7 hours and 3/4 hours into a decimal number.  This will help when doing equations (the work).

This means finding the decimal value of 3/4.  3 divided by four is .75, which means that's the decimal value.  Now add 7.

The full decimal number is 7.75 hours.

Now, the question says you are two-thirds there, meaning you have one-third to get there, also known as 1/3.  

What you can do to find how much longer the trip will take is divide 7.75 by 3 which will give you one-third of 7.75.  

One-third of 7.75 is 7.75 divided by 3 which is approximately equal to 2.58.

Since the unit is hours, 2.58 represents 2.58 hours.

Therefore, the answer is that it will take 2.58 hours longer to get to Portland, Orgeon.

Remember to do a bit of studying, understand how the question can be solved, and doing procedures with fractions.

I hope this helped!




8 0
2 years ago
Jessica won $800,000 in a state lottery. After paying $320,000 in taxes, she invested the remaining money in a savings account a
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4 0
2 years ago
Writing two column proofs<br> Given: BC bisects. ABD M ABD =52° prove: mABC=26°
Artemon [7]

Given

BC bisects ABD

∠ ABD =52°

prove: m ∠ABC=26°

To proof

As given in the question

BC bisects ∠ABD

This means BC divided ∠ABD into the two equal parts.

Therefore

\angle ABC = \frac{1}{2}\angle ABD

As given

∠ABD = 52°

put this in the above value

we get

\angle ABC =\frac{1}{2}52^{\circ}

∠ABC = 26°

Hence proved

 


8 0
2 years ago
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A number, y, is equal to the difference of a larger number and 3. The same number is one-third of the sum of the large number an
Aleonysh [2.5K]
<span>Let the larger number be x.

</span><span>A number, y, is equal to the difference of a larger number and 3.

y = x - 3

x - y = 3

</span>The same number is one-third of the sum of the large number and 9.

y = (1/3)(x + 9)

3y = x + 9

x - 3y = -9

The equations are:
x - y = 3
x - 3y = -9
5 0
2 years ago
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