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anzhelika [568]
2 years ago
4

Assume the existence of a Phone class. Define a derived class, CameraPhone that contains two data members: an integer named, ima

geSize, representing the size in megabytes of each picture, and an integer named memorySize, representing the number of megabytes in the camera's memory. There is a constructor that accepts two integer parameters corresponding to the above two data members and which are used to initialize the respective data members. There is also a function named numPictures that returns (as an integer) the number of pictures the camera's memory can hold.
Computers and Technology
1 answer:
inysia [295]2 years ago
4 0

#include <iostream>

using namespace std;

class CameraPhone:Phone{

int imageSize,memorySize;

public:

CameraPhone(int image_size,int memory_size):imageSize(image_size),memorySize(memory_size){}

int numPictures(){

return memorySize-imageSize;

}

}

int main(){}

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JulijaS [17]
The fourth choice is correct.
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2 years ago
What conclusion can be made about the state of the program when the while loop terminates? Assume answer is a declared and initi
stellarik [79]

<u>Answer:</u>

<em>1. The loop will run unless the value of answer equals to Capital N.</em> The method equals is “case-sensitive” that is lower case letter and upper case letters are considered different. That “a” and “A” means the same to us, but for the method equals it is different and equals method will return false if the case is not matching.

<em>2. a (int)(Math.random() * (upper − lower) ) + lower </em>

Since we need to consider the lower limit value together to get the desired results we need to add the value of lower limit to the multiplied answer.

<em>3. b while(userGuess != secretNumber || userGuess >= lowerLimit && userGuess <= upperLimit)</em>

Here the program is required to check the while loop and exit when user guess the number or we can say the loop should continue until the user guess the number, so that is why we have taken <em>userGuess!=secretNumber. </em>Next the loop should be exited if it is not within the range or we can say that the loop should run only if the guessed number is within the upper and lower limit.<em> That is why we have opted for the condition userGues>=lowerlimit && userGuess<=upperlimit.</em> Why we have taken && as the operator is that, it’s a range of values so && operator best suit for this kind of logical condition.

3 0
2 years ago
A layer 2 switch is used to switch incoming frames from a 1000base-t port to a port connected to a 100base-t network. which meth
fredd [130]
<span>Shared memory buffering would work best. This would give the ports the best allocation of resources, using only those that are the most active and best allocated for the size of the frames being transmitted in the current traffic. In addition, any port can store these frames, instead of being specifically allocated as per other types of memory buffering.</span>
7 0
2 years ago
When an author produce an index for his or her book, the first step in this process is to decide which words should go into the
Igoryamba

Answer:

import string

dic = {}

book=open("book.txt","r")

# Iterate over each line in the book

for line in book.readlines():

   tex = line

   tex = tex.lower()

   tex=tex.translate(str.maketrans('', '', string.punctuation))

   new = tex.split()

   for word in new:

       if len(word) > 2:

           if word not in dic.keys():

               dic[word] = 1

           else:

               dic[word] = dic[word] + 1

for word in sorted(dic):

   print(word, dic[word], '\n')

                 

book.close()

Explanation:

The code above was written in python 3.

<em>import string </em>

Firstly, it is important to import all the modules that you will need. The string module was imported to allow us carry out special operations on strings.

<em>dic = {} </em>

<em>book=open("book.txt","r") </em>

<em> </em>

<em># Iterate over each line in the book</em>

<em>for line in book.readlines(): </em>

<em> </em>

<em>    tex = line </em>

<em>    tex = tex.lower() </em>

<em>    tex=tex.translate(str.maketrans('', '', string.punctuation)) </em>

<em>    new = tex.split() </em>

<em />

An empty dictionary is then created, a dictionary is needed to store both the word and the occurrences, with the word being the key and the occurrences being the value in a word : occurrence format.

Next, the file you want to read from is opened and then the code iterates over each line, punctuation and special characters are removed from the line and it is converted into a list of words that can be iterated over.

<em />

<em> </em><em>for word in new: </em>

<em>        if len(word) > 2: </em>

<em>            if word not in dic.keys(): </em>

<em>                dic[word] = 1 </em>

<em>            else: </em>

<em>                dic[word] = dic[word] + 1 </em>

<em />

For every word in the new list, if the length of the word is greater than 2 and the word is not already in the dictionary, add the word to the dictionary and give it a value 1.

If the word is already in the dictionary increase the value by 1.

<em>for word in sorted(dic): </em>

<em>    print(word, dic[word], '\n') </em>

<em>book.close()</em>

The dictionary is arranged alphabetically and with the keys(words) and printed out. Finally, the file is closed.

check attachment to see code in action.

7 0
2 years ago
Kris, an IT manager at Park Infosystems, is handling four projects simultaneously. Each project has loaned and shared resources
Natalija [7]

Answer:

many-to-many relationship

Explanation:

They are different types of relationship between projects. A many-to-many relationship occurs when a row in a table associates with many related rows in another table. For example the relationship between an employee and a project, An employee can work on many projects and a project can have many employees working on it.

8 0
2 years ago
Read 2 more answers
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