The basics would be that you'd need to find out if they could exchange genetic information. If not, they couldn't be considered part of one species. Set-up 2 artificial environments so both groups would produce pollen at the same time. Fertilise both plants with the other's pollen. Then fertilise the plants with pollen from their own group.
Count the number of offspring each plant produces.
If the plants which were fertilised by the opposite group produce offspring, they are of the same species. You can then take this further if they are of the same species by analysing if there is any difference between the number (and health) of offspring produced by the crossed progeny and by the pure progeny. You'd have to take into account that some of them would want to grow at different times, so a study of the progeny from their first sprout until death (whilst emulating the seasons in your ideal controlled environment). Their success could then be compared to that of the pure-bred individuals.
Make sure to repeat this a few times, or have a number of plants to make sure your results are accurate.
Or if you couldn't do the controlled environment thing, just keep some pollen one year and use it to fertilise the other group.
I'd also put a hypothesis in there somewhere too.
The independent variable would be the number of plants pollinated. The dependant variable would be the number of progeny (offspring) produced.
Simple problem my friend!
First we must replace X with -2,-1,0,1,2
then we plug in -2 in X. 8*-2 is -16 and adding 12 gives us a co ordinate of (-2,-4) now this is not enough so now we must do -1. 8*-1 is -8, + 12 gives us 4. so now our second co ordinate is (-1,4). i will do 1 more co ordinate and then you should be able to finish the problem by yourself :) we now plug in 0 to replace X. 8*0 is 0, easy and 0+12 is 12. so the third co ordinate is (0,12) when you have put all the dots on the graph be sure to draw a line through them and by the way, this is not a biology question lol, good luck!
<h2>The Forearm</h2>
Explanation:
The proximal end of the radius illustrates the relationship of form and function. The cup-like surface of the radial head articulates with the rounded shape of the capitulum. This forms a joint that allows for movement of elbows and forearms.
Radius and ulna are the two bones of the forearm. Their proximal ends articulate and fit into the cup like end of the humerus. This forms a synovial joint called the elbow joint. The movement of this joint allows the forearms to supinate and pronate.
<span>To find the number of trees per hectare, simply divide the two figures together. 11,025 (the number of trees) divided by 3,150 (the number of overall hectares in the plot of land) gives a value of 3.5 trees per hectare.</span>
<u>Answer:</u>
<em>Caurepa taxifolia is an invasive species of algae and is listed in the IUCN list of 100 invasive species.
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<u>Explanation:</u>
In is an algae usually found in the pacific ocean. It was earlier used in aquariums as an <em>ornamental species of algae</em>. The dangerously invasive nature overshadows its attractive appearance.
It is inedible and increases in numbers at a surprisingly <em>accelerated rate.</em> The growth of other plants is difficult in areas dominated by the Caurepa taxifolia. The introduction of this <em>algae was in the Meditteranian sea.
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