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damaskus [11]
2 years ago
14

Which statement correctly describes the nuclear envelope of a eukaryotic cell? See Concept 6.3 (Page 102) View Available Hint(s)

Which statement correctly describes the nuclear envelope of a eukaryotic cell? See Concept 6.3 (Page 102) The nuclear envelope is a single membrane, consisting of a phospholipid bilayer. Plasmadesmosomes in the nuclear envelope permit the exchange of macromolecules between the nucleus and the cytoplasm. All of the proteins of the cell are synthesized on ribosomes bound on the nuclear envelope. The nuclear envelope is continuous with the endoplasmic reticulum. The outer layer of the nuclear envelope is coated with laminin.
Biology
1 answer:
netineya [11]2 years ago
8 0

The correct answer is: The nuclear envelope is continuous with the endoplasmic reticulum

The nuclear envelope or nuclear membrane is composed of two phospholipid bilayers (outer and inner) that surround the nucleus in the eukaryotic cell. The space between the outer and inner membranes is called the perinuclear space. The nuclear envelop has nuclear pores that are responsible for the transport between nucleus and cytoplasm (e.g. transport of mRNA).

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The tentacles of a squid are appendages that have been modified from which primitive molluscan structure?
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2 years ago
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Which of the following best describes a production quota​?
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Place the following events of excitation in the correct order. 1) ion channels on the sarcolemma open and sodium ions enter the
Gre4nikov [31]

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4, 3 5, 1, 2.

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The Ach, binds with the receptors in the sarcolemma, leading to opening of Ligand gated Na+ channels. Therefore Na+diffuses in, causing depolarization, and propagation of action potential along the sarcolemma  spreading to the  T-tubules.

This is followed by opening of Calcium channels leading  exist of Ca+ from the sarcoplasmic reticulum.

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6 0
2 years ago
A boy threw a small bundle toward his girlfriend on a balcony 10. meters above him. The bundle stopped rising in 1.5 seconds. Ho
Alisiya [41]

Hi!


We know that the boy must have thrown the bundle with some initial velocity 'v', and that the bundle stops after 1.5 seconds at a height 's' with a final velocity 'u' -which would be 0.

Our known values thus are:

Time (t) = 1.5 s

Final velocity (u) = 0 m/s

Gravitational acceleration (g) = -9.8 m/s^(2)

<em>Note: that the acceleration is negative as it is opposing the direction of motion (acting  down on the object, causing deceleration)</em>

We will be using <em>equations of motion for an accelerating object</em> to solve first for initial velocity, in order to find the distance.

<h3>Initial Velocity using     <u>v = u + at</u></h3>

Rearranging the equation, and using the value 'g' as our acceleration, we get,<em> u = v - at</em>

u = 0 - (-9.8)(1.5) = 14.7m/s

<h3>Distance Travelled using   <u>v^2 = u^2 + 2as</u></h3>

Rearranging the equation, we get, <em>s= v^(2) - u^(2) / 2a</em>

s = 0^(2) - 14^(2) / 2(-9.8)                          

<em>Note: the negative sign is not a part of the initial velocity, but a part of the equation </em>

s = - 216.09 / -19.6 = 11.025 m


The distance traveled by the bundle is hence, ~ 11 meters, which is high enough for the girl to catch.


Hope this helps!


6 0
2 years ago
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