Consider the ratio of 153 per 108. Write this ratio in different forms below. A ratio written as a reduced fraction: ____ A rati
1 answer:
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Answer:
he can expect to lose 0.5$
Step-by-step explanation:
To solve this problem we must calculate the expected value of the game.
If x is a discrete random variable that represents the gain obtained when rolling a dice, then the expected value E is:
When throwing a dice the possible values are:
x: 1→ -$9; 2→ $4; 3→ -$9; 4→ $8; 5→ -$9; 6→ $12
The probability of obtaining any of these numbers is:
The gain when obtaining an even number is twice the number.
The loss to get an odd number is $ 9
So the expected gain is:
Answer:
The number of rainfalls is
The answer to the second question is no it will not be valid this because from the question we are told that the experiment require one pH reading per rainfall so getting multiply specimens(used for the pH reading) from one rainfall will make the experiment invalid.
Step-by-step explanation:
from the question we are told that
The standard deviation is
The margin of error is
Given that the confidence level is 95% then we can evaluate the level of significance as
Next we will obtain the critical value of from the normal distribution table , the value is
Generally the sample size is mathematically represented as
substituting values
The answer to the second question is no the validity is null this because from the question we are told that the experiment require one pH reading per rainfall so getting multiply specimens(used for the pH reading) from one rainfall will make the experiment invalid
Answer:
There cannot be equal errors in both and yellow has fewer errors.
Step-by-step explanation:
we can do paired t test for these two colours
(one tailed test)
df = 9
The data can be tabulated as follows:
Yellow white
5 7
2 6
6 8
7 5
2 9
5 11
3 8
8 3
4 6
9 10
t-Test: Paired Two Sample for Means
Yellow white
Mean 5.1 7.3
Variance 5.877777778 5.788888889
Observations 10 10
Pearson Correlation -0.139051655
Hypothesized Mean Difference 0
df 9
t Stat -1.908439275
P(T<=t) one-tail 0.044341411
t Critical one-tail 1.833112923
P(T<=t) two-tail 0.088682822
t Critical two-tail 2.262157158
Since p value one tailed = 0.0443 and it is <0.05 our significance level, we reject null hypothesis.
There cannot be equal errors in both and yellow has fewer errors.