Answer:
Start the algorithm and check the weight of the ship. Load the crystalline to the ship. Check to see if the ship weighs ship weight + k pound crystalline, if less, add more crystalline. If excess, remove the excess crystalline, but if the weight meets the condition, then take off with the loaded ship to planet sigma.
Explanation:
The algorithm continuously checks the weight of the ship on loading with the calculated sum of the ship and k pound crystalline weight. The ship is able to load the correct maximum amount of crystalline to the planet sigma.
They are probably looking for B. subscribing to journals is a good way of keeping up with what's happening in any field.
Of course, a very carefully curated professional network online is great for this too (but they said "personal" so that's not the answer)
Employers generally prefer that employees WORK as often as possible, so even though JUDICIOUS use of social media is a great way to keep current, D isn't the answer either.
Blogging about personal experiences is not necessarily going to teach you anything about work, though blogging professionally can be useful in gathering response from your readership
Code:
public static int[] reverse(int [] arr){
Int [] newArr = new int[arr.length];
for (int k = 0; k<arr.length;k++){
/*Missing statement */
}
return newArr;
Answer:
Replace the comment with:
newArr[k] = arr[arr.length-k];
Explanation:
Required
Complete the code
In the given code:
The first line of the given code defines the method
public static int[] reverse(int [] arr){
The next line declares array newArr withe same length as array arr
Int [] newArr = new int[arr.length];
The next line iterates through the elements of array arr
for (int k = 0; k<arr.length;k++){
The /* Missing statement */ is then replaced with:
newArr[k] = arr[arr.length-k];
The above statement gets the elements of array arr in reversed order.
This is so because, as the iteration iterates through array arr in ascending order, arr.length-k gets the element in reversed order
This is an incomplete question. The complete question is given below:
Mike has never used slide presentation software before but he needs to create a presentation by the end of the week what resource would be most helpful to mike
a. The 350-page printed manual from the slide presentation software publisher
b. A free tutorial the slide presentation software publisher has posted on the company website
c. A trouble-shooting website created by a third party
d. The 350-page online manual from the slide presentation software publisher
Answer:
b - A free tutorial the slide presentation software publisher has posted on the company website
Explanation:
As Mike has a short time and no prior experience with a slide software, then in this scenario, the best, simplest and fastest way to learn and create a presentation a free tutorial which the slide presentation software publisher has posted on the company website as this is the same company that has created this particular software so he can be rest-assured that the resource he is relying on is authentic and up-to-date with information on latest features.
Moreover, it's efficient and quick way to learn from a free tutorial rather than from 350-page printed or online manual especially for a beginner.
Besides, his purpose is to create the presentation using the software and not trouble-shooting so trouble-shooting website created by a third party is not useful for him and it also might not be authentic or updated as well.