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RSB [31]
2 years ago
3

5. What happens when more than one keyword appears in a string? Consider the string "My mother has a dog but no cat." Explain ho

w to prioritize responses in the reply method. Did this impact any changes you made to the getResponse method?
Computers and Technology
1 answer:
disa [49]2 years ago
8 0

Answer:  

Please see below  

Explanation:  

When this is the case, the prioritizing will be done on the basis of whichever keyword came first in the string - it is that particular method that will be called. Hence, if you wish to prioritize the method available for pets over the method available for family, you will need to place it as such in the source code - and this is how the getResponse method will be impacted.

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python Consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". Any value that is the same as the immediately preceding value i
Vika [28.1K]

int firstNumber,secondNumber = -1, duplicates = 0;

do {

cin >> firstNumber;

if ( secondNumber == -1) {

secondNumber = firstNumber;

}else {

if ( secondNumber == firstNumber )

duplicates++;

else

secondNumber = firstNumber;

}

} while(firstNumber > 0 );

cout << duplicates;

7 0
2 years ago
The budget process which emphasizes the achievement of goals and competition between alternatives is:
Maslowich

The question has multiple choices;


<span>A) </span>Incremental budgeting.
B) Performance budgeting.
C) Program budgeting.
D) Target based budgeting.


I’d say D is the answer; Target based budgeting


Target based budgeting focuses on the achievement of goals and competition. Prices in Target based budgeting are used as a tool to make or break sales. This method includes researching the markets to decide at what exact price a product will sell.






4 0
2 years ago
The term that refers to the programmer reading the program from the beginning and stepping through each statement is _________.
Wewaii [24]

Answer: Desk checking

Explanation:

 The desk checking is one of the type of informal way manual testing in which the programmer use this method for evaluating or checking the coding or the different types of algorithm logic in the system.

  • It helps in identifying the errors in the program so that it can be executed properly without any interruption in the system.
  • It is one of the effective way for the error detection and also known as the modern debugging tool.

According to the given question, the desk checking is the term which is used to refers to the programmers for reading the given program step by step each statement. Therefore, Desk checking is the correct answer.

Therefore, Desk checking is the correct answer.

5 0
2 years ago
Define a class named ComparableSquare that extends Square (defined above) and implements Comparable. Implement the compareTo met
Alexxx [7]

Answer:

/*********************************************************************************

* (The ComparableCircle class) Define a class named ComparableCircle that        *

* extends Circle and implements Comparable. Draw the UML diagram and implement   *

* the compareTo method to compare the circles on the basis of area. Write a test *

* class to find the larger of two instances of ComparableCircle objects.         *

*********************************************************************************/

public class Exercise_13_06 {

/** Main method */

public static void main(String[] args) {

 // Create two instances of ComparableCircle objects

 ComparableCircle comparableCircle1 = new ComparableCircle(12.5);

 ComparableCircle comparableCircle2 = new ComparableCircle(18.3);

 // Display comparableCircles

 System.out.println("\nComparableCircle1:");

 System.out.println(comparableCircle1);

 System.out.println("\nComparableCircle2:");

 System.out.println(comparableCircle2);

 // Find and display the larger of the two ComparableCircle objects

 System.out.println((comparableCircle1.compareTo(comparableCircle2) == 1  

  ? "\nComparableCircle1 " : "\nComparableCircle2 ") +  

  "is the larger of the two Circles");

}

}

3 0
2 years ago
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
2 years ago
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