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tiny-mole [99]
2 years ago
7

How many different letter permutations, of any length, can be made using the letters M O T T O (For instance, there are 3 possib

le permutations of length 1.)
Mathematics
1 answer:
Tatiana [17]2 years ago
5 0

Answer:

89

Step-by-step explanation:

Given that

2 O, 2 T and 1 M

Now based on this, the following ways are there  

1

Three ways i.e. {M,T,O}

2

XX or XY

XX in 2C1 = two ways i.e. {OO or TT}

XY in 3C2 × 2! = six ways

3

XXY or XYZ

XXY in 2C1 × 2C1 × 3! ÷ 2! = twelve ways

XYZ in 3C3 × 3! = six ways

4

XXYY or XXYZ

XXYY = 4! ÷ (2! × 2!) = six ways

XXYZ in 2C1 ×  4! ÷ 2! = twenty four ways

5

= 5! ÷ (2! ×2!)

= 120 ÷ 4

= 30

Therefore, the total is

= 3 + (2 +6)+ (12 +6) + (6 +24) + 30

= 89

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The curvature of the Tacoma Narrows Bridge in
8_murik_8 [283]

Answer:

Width of the arch = 105 m

Step-by-step explanation:

Function representing the width of the arch,

f(x) = -0.016(x - 52.5)² + 45

where x = width of the base of the arch or horizontal distance from arch's left end

f(x) = vertical distance of the arch

From the given quadratic function, vertex of the parabola is (52.5, 45).

Coordinates of the vertex represents,

Height of the arch = 45 m

Half of the horizontal distance from the left end = 52.5 m

Therefore, width of the bridge = 2(Half the width of the bridge from left end) = 2×52.5

= 105 m

Therefore, given bridge is 105 m wide.

4 0
2 years ago
Just the question about sandy))<br><br>A &amp; B
hammer [34]
A.) 50.45m + 60 = 57.95m

b.) 50.45m + 60 = 57.95m
     60 = 57.95m - 50.45m
     60 = 7.50m
     60 / 7.50 = m
     8 = m.....so the cost will be the same at 8 months

7 0
2 years ago
Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes
Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2\times 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 \times 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled \triangle AOB.

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = \dfrac{Total\ distance}{Total\ time}

\Rightarrow \dfrac{74.28}{5} = 14.86\ knots

6 0
2 years ago
Hannah has 127 books in her collection. Her school is hosting a book donation. There are z students at her school, and they each
luda_lava [24]

127 \div z
8 0
2 years ago
jim says that the output of the floor function is the number before the decimal point in the input. For what domain is Jim’s sta
Mila [183]

Jim’s statement is correct for all numbers greater than or equal to 0. It does not work for negative numbers. For example, the floor of –3.5 is –4, where –4 is not equal to –3, the number before the decimal point. Hope this helps!

Thanks!

-Charlie

7 0
2 years ago
Read 2 more answers
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