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Gelneren [198K]
2 years ago
3

Examine the ratios to find the one that is not equivalent to the others. StartFraction 2 Over 5 EndFraction = StartFraction 6 Ov

er 10 EndFraction = StartFraction 8 Over 20 EndFraction = StartFraction 12 Over 30 EndFraction Which ratio is different from the other three? StartFraction 8 Over 20 EndFraction StartFraction 12 Over 30 EndFraction StartFraction 6 Over 10 EndFraction StartFraction 14 Over 35 EndFraction
Mathematics
2 answers:
romanna [79]2 years ago
7 0

Answer:

StartFraction 6 Over 10 EndFraction

Step-by-step explanation:

Give the following ratios :

2 / 5 = 6 /10 = 8 / 20 = 12 / 30

Which ratio is different from the other three?

Ratio 1 = 2 / 5

Ratio 2 = 6 / 10

Ratio 3 = 8 / 20

Ratio 4 = 12 / 30

Reducing all the ratios to their lowest term:

Ratio 1 = 2 / 5

Ratio 2 = 3 / 5

Ratio 3 = 2 / 5

Ratio 4 = 2 / 5

Hence, the ratio which is different from the other three is StartFraction 6 Over 10 End Fraction (6 / 10)

swat322 years ago
6 0

Answer:

StartFraction 6 Over 10 EndFraction

Step-by-step explanation:

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2 years ago
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The heights of students in a class are normally distributed with mean 55 inches and standard deviation 5 inches. Use the Empiric
maks197457 [2]

Answer:  c)[50,60]

Step-by-step explanation:

The Empirical rule says that , About 68% of the population lies with the one standard deviation from the mean (For normally distribution).

We are given that , The heights of students in a class are normally distributed with mean 55 inches and standard deviation 5 inches.

Then by Empirical rule, about 68% of the heights of students lies between one standard deviation from mean.

i.e. about 68% of the heights of students lies between \text{Mean}\pm\text{Standard deviation}

i.e. about 68% of the heights of students lies between 55\pm5

Here, 55\pm5=(55-5, 55+5)=(50,60)

i.e.  The required interval that contains the middle 68% of the heights. = [50,60]

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4 0
2 years ago
A rectangular plot of land that contains 1500 square meters will be fenced and divided into two equal portions by an additional
WINSTONCH [101]
Let x = the length of the rectangle
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Two sections are required, hence 2w of fence required
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this can be written as:
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Area=x*w
replacing w with our expression:
A=x(1500-2x)/3
A=(500x-2x^2)/3

This is a quadratic equation, if we find the axis of symmetry we will know what value of x gives maximum area:
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2 years ago
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Paha777 [63]

Answer:

Step-by-step explanation:

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b = ?

1/2 × 24 ( 30 + b ) = 864

12 ( 30 + b ) = 864

30 + b = 864/12

30 + b = 72

b = 72 - 30

b = 42

Therefore the lenght of other base = 42 cm

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Answer:

I think it is maybe 19% but Idk.

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