Answer:
The value of q that maximize the profit is q=200 units
Step-by-step explanation:
we know that
The profit is equal to the revenue minus the cost
we have
---> the revenue
---> the cost
The profit P(q) is equal to

substitute the given values



This is a vertical parabola open downward (because the leading coefficient is negative)
The vertex represent a maximum
The x-coordinate of the vertex represent the value of q that maximize the profit
The y-coordinate of the vertex represent the maximum profit
using a graphing tool
Graph the quadratic equation
The vertex is the point (200,-120)
see the attached figure
therefore
The value of q that maximize the profit is q=200 units
Answer:
The price would be decreased by 18 bozats
Step-by-step explanation:
The following information is given in the question
x = number of kilograms of snig sold
P = Price per kilogram
And, the equation is
p = 300 - 18x
Now if an extra kilogram is sold so it should be x+1
Now the new price is
New price = 300 - 18(x + 1)
= 300 - 18x - 18
Therefore the price would be decreased by 18 bozats
Answer:
(SEE EXPLANATION FIRST)
Answer D is TRUE because on the graph if you were to keep going left even after the picture of the graph ends, the graph will still keep going up infinite
Step-by-step explanation:
If this is the graph you can read the answer