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Alona [7]
1 year ago
8

What number is 35 times larger than 452?

Mathematics
2 answers:
Ghella [55]1 year ago
8 0
15820 would be the right answer
posledela1 year ago
6 0

Answer:

i think it is 15820

Step-by-step explanation:

You might be interested in
A log is 16m long, correct to the nearest metre. It has to be cut into fence posts which must be 70cm long, correct to the neare
dmitriy555 [2]

Answer:

25 posts

Step-by-step explanation:

So the number of fence post would be the total length of the log divided by the length of each post. As the log is 16m and is corrected to the nearest metre, it could possibly be 16.499m. As for the post that is 70 cm long and corrected to the nearest 10cm, it may as well be 65 cm (or 0.65m) each post

So the max number of fence point once can possibly cut from the log would be

16.499 / 0.65 = 25 posts

5 0
1 year ago
The entire universe of computer games are made up of:
expeople1 [14]

Answer:

Math properties the programmer had put into the software. The majority of programming software is based in math.

Step-by-step explanation:

The other 3 possible answers make no sense.

1. Pixels with red, green, and blue switches - Seriously???

2. Code randomly created by programmers - Seriously???

3. The fundamental properties of physics which consist of numbers and constants (numbers and constants are the same thing and physics has virtually nothing to do with programming)

4 0
2 years ago
[Q71 Suppose that the height, in inches, of a 25-year-old man is a normal random variable with parameters g = 71 inch and 02 = 6
viktelen [127]

Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

              (b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

Step-by-step explanation:

Given that,

                  Height (in inches) of a 25 year old man is a normal random variable with mean g=71 and variance o^{2} =6.25.

To find:  (a) What percentage of 25 year old men are 6 feet, 2 inches tall

               (b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.

Now,

(a) To calculate the percentage of men, we have to calculate the probability

P[Height of a 25 year old man is over 6 feet 2 inches]= P[X>74in]

                           P[X>74] = P[\frac{X-g}{o} > \frac{74-71}{2.5}]

                                         = P[Z > 1.2]

                                         = 1 - P[Z ≤ 1.2]

                                         = 1 - Ф (1.2)

                                         = 1 - 0.8849

                                         = 0.1151

Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X, 6ft 5in - X, 6ft]

     P[X > 6ft 5in I X > 6ft] = P[X > 77 I X > 72]

                                          = \frac{P[X > 77]}{P[ X > 72]}

                                          = \frac{P[\frac{X - g}{o}>\frac{77-71}{2.5}]  }{P[\frac{X-g}{o} >\frac{72-71}{2.5}] }

                                          = \frac{P[Z >2.4]}{P[Z>0.4]}

                                          =  \frac{1-P[Z\leq2.4] }{1-P[Z\leq0.4] }

                                          = \frac{1-0.9918}{1-0.6554}

                                          = \frac{0.0082}{0.3446}

                                          = 0.024

Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

4 0
2 years ago
chen is buying a ham. He wants to divide it into 6.5-ounce servings for 12 people. write and solve a division equation to find w
OLga [1]

Answer:

Amount of people to serve x Serving Size = Size of ham

12 x 6.5 = ?

=78

Step-by-step explanation:

Looking for size ham chen should buy = ?

Amount of people to serve = 12

Serving Size = 6.5-ounce

Equation=

Amount of people to serve x Serving Size = Size of ham

12 x 6.5 = ?

=78

8 0
2 years ago
use the polygon tool to draw an image of the given polygon under a dilation with a scale factor of 1/3 and center of dilation at
Sveta_85 [38]

Answer:

x-y and AxR

Step-by-step explanation:

5 0
1 year ago
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