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Dmitriy789 [7]
2 years ago
10

Select the level of education that is best demonstrated in each example.

Engineering
2 answers:
Nastasia [14]2 years ago
8 0

Answer:

masters

associate

bachelors

Explanation:

dangina [55]2 years ago
6 0

Answer:

1, 2, 1 or A, B, A

Explanation:

I just wanted free points brrrr

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. A cylindrical metal specimen having an original diameter of 12.8 mm (0.505 in.) and gauge length of 50.80 mm (2.000 in.) is pu
kogti [31]

Answer:

% reduction in area==PR=0.734=73.4%

% elongation=EL=0.42=42%

Explanation:

given do=12.8 mm

df=6.60

Lf=72.4 mm

Lo=50.8 mm

% reduction in area=((\pi*(do/2)^2)-(\pi*(df/2)^2)))/\pi*(do/2)^2

substitute values

% reduction in area=73.4%

% elongation=EL=((Lf-Lo)/Lo))*100

% elongation=((72.4-50. 8)/50.8)*100=42%

6 0
2 years ago
A shopaholic has to buy a pair of jeans , a pair of shoes l,a skirt and a top with budgeted dollar.Given the quantity of each pr
fredd [130]

Answer:

you might be facing some difficulty in observing this point of division between your question and me

0 0
2 years ago
At a certain elevation, the pilot of a balloon has a mass of 120 lb and a weight of 119 lbf. What is the local acceleration of g
Crank

Answer:

1) g=31.87ft/s^2

2)m=120

W=119.64lbf

Explanation:

first part

the weight of a body with mass is calculated by the following equation

W=mg

we convert 120lb to slug

m=120lbx1slug/32.147lb=3.733slug

solving for g

g=W/m

g=119/3.733=31.87ft/s^2

second part

the mass is the same

m=120lb=3.733slug

Weight

W=3.733slug*32.05ft/s^2=119.64lbf

4 0
2 years ago
In a cellular phone system, a mobile phone must be paged to receive a phone call. However, paging attempts don’t always succeed
Alina [70]

Answer:

The correct response will be "0.992". The further explanation to the following question is given below.

Explanation:

The probability that paging would be beneficial becomes 0.8  

Effective paging at the very first attempted is 0.8

On the second attempt the success probability will be:

⇒  0.2\times 0.8

⇒  0.16

On the third attempt the success probability will be:

⇒  0.2\times 0.2\times 0.8

⇒  0.032

So that the success probability will be:

⇒  0.8 + 0.16 + 0.032

⇒  0.992

7 0
2 years ago
Investigate the squared-and-ground-ended helical compression spring shown below to see if it is solid-safe. If not, what is the
dimulka [17.4K]

Answer:

The spring is solid safe since calculated Ns >  given Ns

Explanation:

Given data :

Wire diameter (∝)= 0.148 in

outside coil diameter(OD) = 2.12 in

free length (lo) = 2.5 in

Total coil ( Nt )  = 5.75

material = A227 Hard-drawn steel

attached below is the remaining part of the detailed solution

From Table

A = 140 kpsi.in^{m}, m = 0.190

Sut = A / d^{m}

since given Ns = 1.2 < 1.36 (calculated Ns)   hence the spring is solid safe

7 0
2 years ago
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