Answer:
5.14 mi/h
Step-by-step explanation:
To find the average speed, we simply find the total distance traveled by Tom and divide that by the total time the entire journey took him.
Average speed = (total distance traveled) / (total time taken)
TOTAL DISTANCE TRAVELED
He traveled 3 miles to and 3 miles fro. Hence:
3 + 3 = 6 miles
TOTAL TIME TAKEN
He spent ½ hr to go and ⅔ hr to return back. Hence:
½ + ⅔ = 7/6 hr
Therefore, the average speed is:
v = 6 / (7/6)
v = 36 / 7 = 5.14 mi/h
Tom's average speed was 5.14 mi/h.
Answer:
Check the explanation
Step-by-step explanation:
One way ANOVA
The null and alternative hypothesis for this one way ANOVA is given as below:
Null hypothesis: H0: There is no significant difference in the averages of the scores for the quizzes, exams and final only.
Alternative hypothesis: There is a significance difference in the averages of the scores for the quizzes, exams and final only.
The ANOVA table with calculations can be seen in the attached images below:
In the attached image below, we get the p-value for this one way ANOVA test as 0.0221. We do not reject the null hypothesis if the p-value is greater than the given level of significance and we reject the null hypothesis if the p-value is less than the given level of significance or alpha value.
In the attached image below, we are given that the p-value = 0.0221 and level of significance or alpha value = 0.05, that is p-value is less than the given level of significance. So, we reject the null hypothesis that there is no significant difference in the averages of the scores for the quizzes, exams and final only. This means we conclude that there is a significance difference in the averages of the scores for the quizzes, exams and final only.
Answer:
0.15c-0.072
divide both side by 0.15c
then simplify by the answer then you will get your answer
Step-by-step explanation:
0.15c-0.072
divide both side by 0.15c
then simplify by the answer then you will get your answer