The question in part c is not clear, nevertheless, part a and part b would be solved.
Answer:
a. The first twelve terms are:
1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144.
b. The first ten terms are:
1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.
Step-by-step explanation:
a. Given
an + 2 = an + an + 1
where a1 = 1 and a2 = 1.
a3 = a1 + a2
= 2
a4 = a2 + a3
= 3
a5 = a3 + a4
= 5
a6 = a5 + a4
= 8
a7 = a6 + a5
= 13
a8 = a7 + a6
= 21
a9 = a8 + a7
= 34
a10 = a9 + a8
= 55
a11 = a10 + a9
= 89
a12 = a11 + a10
= 144
The first twelve terms are:
1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144.
(b)
Given
bn = an+1/an
b1 = a2/a1
= 1/1 = 1.000
b2 = a3/a2
= 2/1 = 1.000
b3 = a4/a3
= 3/2 = 1.500
b4 = a5/a4
= 5/3 = 1.667
b5 = a6/a5
= 8/5 = 1.600
b6 = a7/a6
= 13/8 = 1.625
b7 = a8/a7
= 21/13 = 1.615
b8 = a9/a8
= 34/21 = 1.619
b9 = a10/a9
= 55/34 = 1.618
b10 = a11/a10
= 89/55 = 1.618
The first ten terms are:
1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.
