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Nataly_w [17]
2 years ago
5

Predict what would happen to typical animal cells placed in 0.0M and 1.0M sucrose solutions, and explain your prediction. The an

imal cells molar concentration is 2.0M.
Biology
1 answer:
Softa [21]2 years ago
7 0

Answer:

The animal cell will take in water until it eventually swells or burst

Explanation:

Osmosis is an important phenomenon that drives the movement of water across membranes. It is defined as the movement of water molecules from a region of high water concentration/low solute concentration to a region of low water concentration/high solute concentration across a semi-permeable membrane.

In this case, the animal cell with a molar concentration of 2.0M is placed in 0.0M and 1.0M sucrose solutions. This means that the cell is placed in an hypotonic solution (solution with low solute concentration), hence, water will move from the extracellular solution into the animal cell since the solute concentration in the cell is more. The animal cell will begin to swell and eventually burst.

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8 0
2 years ago
A scientist is studying the population of a particular species of beetle in an ecosystem. The beetles currently have an estimate
mr_godi [17]

Answer:

Year Population

1         11,500

2         12,075

3         12,679

4         13,313

5         13,978

6         14,677

Explanation:

5 0
2 years ago
Which information on an autopsy report would be essential for evaluating a suspect's alibi?
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The answer to your question: cause of death.

3 0
2 years ago
Read 2 more answers
Black coat color in horses is conferred by the presence of a dominant B allele. Chestnut horses are genotype bb. A population of
AysviL [449]

Answer:

Frequency of B allele is 0.6681

Explanation:

If p represents the frequency of dominant allele and q represents the frequency of  recessive allele, according to Hardy-Weinberg equilibrium:

p + q = 1

p² + 2pq + q² = 1

where p² = frequency of homozygous dominant genotype

q² = frequency of homozygous recessive genotype

2pq = frequency of heterozygous genotype

Given that number of recessive chestnut horse = 28

Total horses = 226 + 28 = 254

frequency of b² genotype = 28/254 = 0.1102

frequency of recessive b allele = √0.1102 = 0.3319

So, frequency of B allele =

1 - 0.3319 = 0.6681

Hence frequency of B allele is 0.6681

7 0
2 years ago
In transcription, _____ is used as a template for the construction of a new rna molecule.
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I think the answer should be B. is the correct answer.  In transcription, a segment of one strand of double stranded DNA.

Hope it helped!
8 0
2 years ago
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