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2 years ago

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A survey of radio stations was conducted following the attacks on the World Trade Center in 2001. One of the variables recorded

was the region in which the station was located (east, center, or west). In addition to the variable "region," the following information was collected: the quartile of the media market (top, second, third, and fourth), state, rank (a number between 1 and 205), and share (a number between 0 and 7). The modified boxplot of station ranks above identifies how many outliers?

1 answer:

vitfil [10]2 years ago

8 0

Answer:

The answer is "All of the answer options are correct".

Step-by-step explanation:

In the given question, the choice and the image file are missing, that is defined in the attached file, please find it.

In the given question, all choices are correct, which can be defined as follows:

Its bottom line indicates the minimal level, in which all others will be the same.
Its middle line throughout the box displays the median value, which also for both is different.
Its total boxplot length is higher for both the shore, demonstrate higher variance.

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On a coordinate plane, 2 polygons are shown. Polygon A B C D has points (1, negative 6), (5, negative 6), (6, negative 2), and (

irga5000 [103]

Answer:

The correct option is;

Use a scale factor of 2

Step-by-step explanation:

The parameters given are;

A = (1, -6)

B = (5, -6)

C = (6, -2)

D = (0, -2)

A'' = (1.5, 4)

B'' = (3.5, 4)

C'' = (4, 2)

D'' = ( 1, 2)

We note that the length of side AB in polygon ABCD = √((5 -1)² + (-6 - (-6))²) = 4

The length of side A''B'' in polygon A''B''C''D'' = √((3.5 -1.5)² + (4 - 4)²) = 2

Which gives;

AB/A''B'' = 4/2 = 2

Similarly;

The length of side BC in polygon ABCD = √((6 -5)² + (-2 - (-6))²) = √17

The length of side B''C'' in polygon A''B''C''D'' = √((4 -3.5)² + (2 - 4)²) = (√17)/2

Also we have;

The length of side CD in polygon ABCD = √((6 -0)² + (-2 - (-2))²) = 6

The length of side C''D'' in polygon A''B''C''D'' = √((4 -1)² + (2 - 2)²) = 3

For the side DA and D''A'', we have;

The length of side DA in polygon ABCD = √((1 -0)² + (-6 - (-2))²) = √17

The length of side D''A'' in polygon A''B''C''D'' = √((1.5 -1)² + (4 - 2)²) = (√17)/2

Therefore the Polygon A B C D can be obtained from polygon A''B''C''D'' by multiplying each side of polygon A''B''C''D'' by 2

The correct option is therefore;

Use a scale factor of 2.

3 0

2 years ago

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Describe a triangle for which the centroid, circumcenter, incenter, and orthocenter are the same point. What features of this tr

hjlf

Answer:

An equilateral triangle

Step-by-step explanation:

Because an equilateral has a feature that all sides have the same length and all angles are of the same, it does not matter from which side and peak the centroid, circumcenter, incenter and orthocenter is created, they would always end up at the same point.

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2 years ago

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Polygons QRST and Q’R’S’T’ are shown on the coordinate grid: A coordinate plane with two polygons is shown. Polygon QRST has ver

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2 years ago

It takes 32 hours for a motorboat moving downriver to get from pier A to pier B. The return journey takes 48 hours. How long doe

lina2011 [118]

Answer:

Time taken by the un powered raft to cover this distance is T = 192.12 hr

Step-by-step explanation:

Let speed of boat = u $\frac{km}{hr}$

Speed of current = v $\frac{km}{hr}$

Let distance between A & B = 100 km

Time taken in downstream = 32 hours

$32 = \frac{100}{u +v}$

$u + v = \frac{100}{32}$

u + v = 3.125 ------ (1)

Time taken in upstream = 48 hours

$48 = \frac{100}{u -v}$

$u -v = \frac{100}{48}$

u - v = 2.084 ------- (2)

By solving equation (1) & (2)

u = 2.6045 $\frac{km}{hr}$

v = 0.5205 $\frac{km}{hr}$

Now the time taken by the un powered raft to cover this distance

$T = \frac{100}{v}$

Because un powered raft travel with the speed of the current.

$T = \frac{100}{0.5205}$

T = 192.12 hr

Therefore the time taken by the un powered raft to cover this distance is

T = 192.12 hr

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2 years ago

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A square based brass plate in 4mm high and has a mass of 1.05kg. The density of the brass is 4.2g/cm3, calculate the length of t

Bezzdna [24]

Answer:

$Length = 25cm$

Step-by-step explanation:

Given

Brass Shape: Square

$Density = 4.2g/cm^3$

$Mass = 1.05kg$

$Height = 4mm$

Required

Determine the length of the plate

First, we need to calculate the Volume of the Brass using

$Density = \frac{Mass}{Volume}$

Make Volume the subject of formula

$Volume = \frac{Mass}{Density}$

Substitute 1.05kg for Mass and 4.2g/cm³ for Density

$Volume = \frac{1,05\ kg}{4.2\ g/cm^3}$

Convert 1.05 kg to grams

$Volume = \frac{1.05 * 1000\ kg}{4.2\ g/cm^3}$

$Volume = \frac{1050 \ kg}{4.2\ g/cm^3}$

$Volume = \frac{1050 \ kg}{4.2\ g/cm^3}$

$Volume = 250cm^3$

Next is to determine the Area of the brass;

$Volume = Height * Area$

Substitute 250cm³ for Volume and 4mm for Height

$250cm^3 = 4mm * Area$

Convert mm to cm

$250cm^3 = 4 * 0.1cm * Area$

$250cm^3 = 0.4cm * Area$

Divide both sides by 0.4cm

$\frac{250cm^3}{0.4cm} = \frac{0.4cm * Area}{0.4cm}$

$\frac{250cm^3}{0.4cm} =Area$

$625cm^2 = Area$

$Area = 625cm^2$

Lastly, we'll calculate the length of the brass

Since the brass is square based;

$Area = Length^2$

Substitute 625cm² for Area

$625cm^2 = Length^2$

Take square root of both sides

$\sqrt{625cm^2} = Length$

$25cm = Length$

$Length = 25cm$

<em>Hence, the length of the square brass is 25cm</em>

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2 years ago