<span>The proteins that are embedded in the cell membrane act as channels to transport substances in and out of the cell.</span>
Answer: Plant vegetation so that their roots hold the soil firmly.
Build walls around the farm area.
Add natural fertilizers to the soil.
Soil erosion is a process of removal of top layer of soil which get sediment at some other place due to the affect of agents like wind and water. The superficial upper layers of soil are rich source of nutrients and organic matter and active region for germination of seeds and plant growth. Soil erosion removes these superficial layers making soil less fertile or not fertile and less useful for plant growth.
Plants growing in a vegetation have roots which can hold the soil and will prevent soil erosion from wind and water or any other agent. Building of walls around the farm area will prevent flood water to get inside the farm area and hence, prevents soil erosion by water. Addition of natural fertilizers to the soil adds up nutrients to the soil which facilitate plant growth and plant roots hold the soil therefore, prevents soil erosion.
Answer: The hormones secretin and cholecystokinin target the pancreas, stomach, and gallbladder.
Explanation:
The duodenum secretes two additional hormones. Cholecystokinin (CCK), like enterogastrone, is secreted in response to the presence of fat in the chyme. CCK stimulates the contractions of the gallbladder, injecting bile into the duodenum so that fat can be emulsified and more efficiently digested. The other duodenal hormone is secretin. Released in response to the acidity of the chyme that arrives in the duodenum, secretin stimulates the pancreas to release bicarbonate, which then neutralizes some of the acidity.
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
