Answer:
or
or
or 
Step-by-step explanation:
Since, According to the question,
For each pound the operator’s guess differs from the contestant’s weight, the contestant will receive $3.
And, If a contestant weighing x pounds received $15
Then the guessed weight of contestant = 
But, Again according to the question,
The guessed weight is 120 pounds,
Thus, 
⇒ 
⇒
(by multiplying 3 on both sides)
⇒ 
⇒ 
⇒
( On dividing both sides by 3 )
X + 2y = 5
x = 5 - 2y
2x + 4y = 3
2(5-2y) + 4y = 3
10 - 4y + 4y = 3
10 ≠ 3
5x + 2y = 3
5(5-2y) + 2y = 3
25 - 10y + 2y = 3
-8y = 3 - 25
-8y = -22
y = -22/-8
y = 2.75
6x + 12y = 30
6(5-2y) + 12y = 30
30 -12y + 12y = 30
30 = 30
3x + 4y = 8
3(5-2y) + 4y = 8
15 - 6y + 4y = 8
-2y = 8 - 15
-2y = -7
y = -7/-2
y = 3.5
An inconsistent system is a system of equation that has NO SOLUTIONS.
2x + 4y = 3 is the equation to be paired with x + 2y = 50 to create an inconsistent system.
Answer:
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone ≈ 12.57 m²
Step-by-step explanation:
The given parameters are;
The height of the cone = 5 m
The base radius of the cone = 2 m
The angle which the A
C = 120°
Therefore, we have;
The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone
The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°
∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57
The area of the base of the cone ≈ 12.57 m².
Miriam will have no apples left after the 7th day of baking.
Here is the number of apples she will have after each day starting with after the 1st day of baking.
126, 108(1st day), 90(2nd day), 72(3rd day), 54(4th day), 36(5th day), 18(6th day), 0(7th day).
Each day the number of apples decreases by 18.
The student took 7 tests.
99+98+88+88+88+88+88 = 637
637/7 = 91