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sergey [27]
2 years ago
10

You are a dog breeder and are interested in two traits that you believe are inherited by simple genetic loci glossy (G) coat is

dominant to dull (g) and Long (L) hair is dominant to short (l). You have a pair of dogs that you have been breeding for several years. The mom is glossy long haired and the dad is dull short haired. Over several litters they have produced the following puppies: 18 Glossy Short 16 Dull Long 8 Dull Short 6 Glossy Long What are the parental gametes produced by this mom
Biology
1 answer:
Paul [167]2 years ago
5 0

Answer:

GL, Gl, gL, and gl

Explanation:

The mom is glossy long haired. Since glossy (G) is dominant over to dull (g) and long hair (L) is dominant to short hair (l), the possible genotypes of the mom would be:

GGLL, GgLL, GGLl, or GgLl

The dad is dull and short haired, the genotype would be ggll.

GGLL   x   ggll

Progeny = all GgLl (all glossy long haired)

GgLL   x   ggll

Progeny = 8 GgLl, 8 ggLi (glossy long haired and dull long haired)

GGLl    x    ggll

Progeny = 8 GgLl, 8 Ggll (glossy long haired and glossy short haired)

GgLl    x    ggll

Progeny = 4 GgLl, 4 Ggll, 4 ggLl, 4 ggll (glossy long, glossy short, dull long, and dull short)

<em>Only a cross of ggll with GgLl produced the offspring that cover the phenotypic range shown in the illustration. Hence, the genotype of the mom is GgLl.</em>

The parental gametes produced by the mom would be; GL, Gl, gL, and gl

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Answer: enzyme dysfunction 

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Sully works as a geologist in the southwestern United States. He plans to choose an unstable isotope to find the absolute age of
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Answer: 3. The half- life of the isotope must be long enough to capture the age of the rock. and

4. their should be more than one unstable isotope.

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3 0
2 years ago
Read 2 more answers
You are a dog breeder and are interested in two traits that you believe are inherited by simple genetic loci glossy (G) coat is
Paul [167]

Answer:

GL, Gl, gL, and gl

Explanation:

The mom is glossy long haired. Since glossy (G) is dominant over to dull (g) and long hair (L) is dominant to short hair (l), the possible genotypes of the mom would be:

GGLL, GgLL, GGLl, or GgLl

The dad is dull and short haired, the genotype would be ggll.

GGLL   x   ggll

Progeny = all GgLl (all glossy long haired)

GgLL   x   ggll

Progeny = 8 GgLl, 8 ggLi (glossy long haired and dull long haired)

GGLl    x    ggll

Progeny = 8 GgLl, 8 Ggll (glossy long haired and glossy short haired)

GgLl    x    ggll

Progeny = 4 GgLl, 4 Ggll, 4 ggLl, 4 ggll (glossy long, glossy short, dull long, and dull short)

<em>Only a cross of ggll with GgLl produced the offspring that cover the phenotypic range shown in the illustration. Hence, the genotype of the mom is GgLl.</em>

The parental gametes produced by the mom would be; GL, Gl, gL, and gl

5 0
2 years ago
For what purpose(s) might a karyotype be prepared?
Lynna [10]

Answer:

The correct answer will be option-C.

Explanation:

A karyotype is the visual representation of the chromosome numbers present in a cell of an organism.

The karyotyping is a technique performed to prepare the karyotype of the organism which plays an important role in analyzing the chromosomal abnormalities of the organism.

The analysis of the chromosomal abnormalities helps us study the genetic disorder and diagnose genetic disease. The karyotyping is performed during pregnancy which helps visualize the disease in a family with a history of genetic disorders.

Thus, Option-C is the correct answer.

4 0
2 years ago
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