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Flura [38]
2 years ago
9

A student analyzed the table below and stated the following, “the y-intercept is 4 because (4,0) has a y value of 0”. Is the stu

dent correct? Why or why not?

Mathematics
1 answer:
Butoxors [25]2 years ago
5 0

Answer:

No

Why he is not correct is because the y-intercept is the coordinate of the point where the graph meets or crosses the y-axis, which is equivalent to a point on the graph where the x-coordinate value reduces to zero, or to put it in a mathematical form x = 0

Step-by-step explanation:

From the given data, we have;

x     {}       y

2     {}      -2

4     {}       0

6      {}      2

8      {}      6

The given data is linear because it has a constant first (common) difference of 2

The general form of the straight line equation is y = m·x + c

Where;

m = The slope

c = The y-intercept

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

The slope of the graph of the data from any two points, (x₁, y₁) = (4, 0) and (x₂, y₂) = (4, 0)) is m = (2 - 0)/(6 - 4) = 1

The equation representing the data in point and slope form is therefore;

y - 4 = 1 × (x - 0)

Which gives;

y = x + 4

Therefore, the y-intercept = 4.

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Which statements accurately describe the function f(x) = 3(StartRoot 18 EndRoot) Superscript x? Select three options. The domain
Studentka2010 [4]

Answer:

The domain is all real numbers.

The initial value is 3

The simplified base is 9\sqrt{2}

Step-by-step explanation:

The given function is f(x)=3(\sqrt{18})^x.

To find the initial value, we put x=0 into the function:  

f(0)=3(\sqrt{18})^0.

f(0)=3(1)=3.

The initial value is actually 3.

The given function is an exponential function, therefore the domain is all real numbers.

The range of this function refers to all values of y for which the function is defined.

The line y=0, is the horizontal asymptote.

The range is y\:>\:0

The simplified base is 3\sqrt{18}=3\sqrt{9\times2}.

3\sqrt{18}=3\sqrt{9}\times\sqrt{2}

3\sqrt{18}=3\times3\times\sqrt{2}

3\sqrt{18}=9\sqrt{2}

4 0
2 years ago
Read 2 more answers
An animal shelter has $2500 in its reserve fund. The shelter charges $40 per animal placement and would like to have at least $4
Elena-2011 [213]

Answer:

Step 1

Write and solve the inequality:

2,500 + 40a ≥ 4,000, or 40a ≥ 1,500

a ≥ 37.5

Step 2

If the shelter places 30 cats and 10 dogs,

or 40 animals, that will be enough to meet

its goal, because a = 40 is a solution to the

inequality a ≥ 37.5.

5 0
2 years ago
A library contains 60,000 books. 14,000 are the subject of business. 22,000 are on healthcare and and 12,000 on psychology and l
PIT_PIT [208]

Answer:

20%

Step-by-step explanation:

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2 years ago
The mean weight of newborn infants at a community hospital is 6.6 pounds. A sample of seven infants is randomly selected and the
Lera25 [3.4K]

Answer:

The correct option is  A

Step-by-step explanation:

From the question we are told that

    The  population is  \mu  =  6.6

     The level of significance is \alpha  =  5\%  = 0.05

      The sample data is  9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds

The Null hypothesis is H_o  :  \mu =  6.6

 The Alternative hypothesis is  H_a :  \mu  > 6.6

The critical value of the level of significance obtained from the normal distribution table is

                       Z_{\alpha } = Z_{0.05 } = 1.645

Generally the sample mean is mathematically evaluated as

      \=x =  \frac{\sum x_i }{n}

substituting values

      \=x =  \frac{9.0 +  7.3 +  6.0+ 8.8+ 6.8+ 8.4+6.6 }{7}

      \=x =  7.5571

The standard deviation is mathematically evaluated as

           \sigma  =  \sqrt{\frac{\sum  [ x -  \= x ]}{n} }

substituting values

          \sigma  =  \sqrt{\frac{  [ 9.0-7.5571]^2 + [7.3 -7.5571]^2 + [6.0-7.5571]^2 + [8.8- 7.5571]^2 + [6.8- 7.5571]^2 + [8.4 - 7.5571]^2+ [6.6- 7.5571]^2 }{7} }\sigma =  1.1774

Generally the test statistic is mathematically evaluated as

            t  =  \frac{\= x - \mu }  { \frac{\sigma }{\sqrt{n} } }

substituting values

           t  =  \frac{7.5571  - 6.6  }  { \frac{1.1774 }{\sqrt{7} } }

            t  = 1.4274

Looking at the value of  t and  Z_{\alpha }   we see that t  <  Z_{\alpha } hence we fail to reject the null hypothesis

  What this implies is that there is no sufficient evidence to state that the sample data show as significant increase in the average birth rate

The conclusion is that the mean is  \mu = 6.6  \ lb

8 0
2 years ago
Classifying the fruit in a basket as apple, orange, or banana, is an example of the ___________ level of measurement?
Serggg [28]

-ratio

-interval

-nominal

-ordinal

Answer:

Nominal

Step-by-step explanation:

-Ratio level of measurement means that you can build a fraction.

-interval level of measurement means that the distance that exists between values is important.

-Nominal means that the values are only named and there is no organization.

-Ordinal means that the values can be ordered by rank.

According to this, the answer is that classifying the fruit in a basket as apple, orange, or banana, is an example of the nominal level of measurement.

3 0
2 years ago
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