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marin [14]
2 years ago
13

How many solutions does this have?​

Mathematics
2 answers:
olga nikolaevna [1]2 years ago
6 0

Answer:

none ok smrbgeriinjhgfd

Hatshy [7]2 years ago
5 0

Answer:

1 solution.

Step-by-step explanation:

These lines cross each other once at the given point. Therefore, the system has <em>1 solution</em>.

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Benito wrote the equations shown about the figure. Explain Benito’s errors.
Minchanka [31]

Answer:

  • Benito's error was using the equal sign (=) instead of the congruency symbol (≅).

Explanation:

Benito's error was using the equal sign (=) instead of the congruency symbol (≅).

The congruency symbol (≅) means that the elements (segments, angles or figures in general) have the same measure, i.e. they have equal lengths for the segments or equal measure for the angles.

For instance, it is an error saying that the segment AB is equal to the segment BC because, as you clearly see in the picture, they are not same; they have the same length but they are joining different points, that makes them different in essence, although they have the same length. They would be equal only if they are the same figure.

In mathematics, you must not say that two different segments or two different angles are equal but they are congruent, which means that their lengths are equal. The use of equal is reserved for numbers and variables, not for figures like segment, points, angles, polygons.

7 0
2 years ago
Name two different numbers that round to 8.21 when rounded to the nearest hundredth
Tanzania [10]
There's an infinite amount of numbers that round to 8.21 when rounded to the nearest hundredth, for example:

8.211
8.209
8.214
8.21145683204
etc...

Just pick whichever two numbers you like :)
8 0
2 years ago
Read 2 more answers
What is three decimals that have a sum of 10.806
White raven [17]

Answer:

  10 + 0.8 + 0.006 = 10.806

Step-by-step explanation:

Pick any two decimal numbers. The third one will be the difference between 10.806 and the sum of the two numbers you picked.

For example, choose 938.2 and 3.0055. Their sum is 941.2055. Then the third number that will make the sum be 10.806 is ...

  10.806 -941.2055 = -930.3995

So, your three numbers could be ...

  {938.2, 3.0055, -930.3995}

7 0
2 years ago
Dilly is 7 years younger than Dally. In 4 years time she will be half Dally’s age. What is the sum of their ages now?
Step2247 [10]

Answer:

<u>The sum of their ages now is 13</u>

Step-by-step explanation:

Dally's age = x

Dilly's age = x - 7

In 4 years time Dilly will be half Dally’s age, therefore:

Dilly's age plus four equals to half of Dally’s age plus four,

replacing with the values and variables we know:

x - 7 + 4 = (x + 4) /2

x - 3 = (x + 4) /2

2x - 6 = x + 4 (Multiplying by 2 at both sides)

2x - x = 4 + 6 (Like terms)

x = 10 ⇒ x - 7 = 3

<u>The sum of their ages now is 13 (10 + 3)</u>

4 0
2 years ago
An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do
vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107

Then,

P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007

c) In this case, the distribution is B(1200,0.01)

P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366

5 0
2 years ago
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