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alexira [117]
1 year ago
10

What is the percent by mass of 8.0g copper is added yo enough zinc to produce 100g an alloy brainly

Biology
1 answer:
kogti [31]1 year ago
6 0

Answer:

8%

Explanation:

Given that,

Mass of solute = 8 g

Mass of soultion, (mass of alloy) = 100 g

We need to find the percent by mass of 8.0g copper is added to enough zinc to produce 100g an alloy. It can be calculated by the formula as follows :

\text{Mass}\%=\dfrac{\text{Mass of solute}}{\text{Mass of solution}}\times 100\\\\=\dfrac{8}{100}\times 100\\\\=8\%

So, the percent by mass is 8%.

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For Heliodorus, having four arm-like extensions is dominant over having two. In a family of Heliodorus, Hayden has four arm-like
IRISSAK [1]

Answer:

Hayden- heterozygous dominant

Mother (Helen)- heterozygous dominant

Father (Harry)- homozygous recessive

Sister (Holly)- homozygous recessive

Explanation:

This is a genetic scenario involving a single gene coding for number of arm-like extensions in Heliodors family. According to the question, the allele for four arm extensions (A) is dominant over thr allele for two arm extensions (a). The question also states that Hayden and his mother have four arm extensions while his sister (Helen) and Father (Harry) have two arm extensions.

Firstly, it is worth it to note that Harry and Holly will be genotypically homozygous recessive (aa) because a recessive trait will only be expressed in a homozygous state, since two arm extensions is the recessive trait.

Now, since father is homozygous recessive, he will produce gametes that contains only "a" allele. If the mother were homozygous dominant (AA), no recessive offspring should be produced because all the offsprings wil phenotypically have four arm extensions. But one has two (recessive) which is the sister (Holly). This is because, although, the mother phenotypically has four, but is genotypically heterozygous dominant (Aa). Hence, it can produce A and a allele in gamete formation. Therefore, Helen has heterozygous dominant (Aa).

Lastly, Hayden also has four arm extensions, hence dominant. But since Aa genotype and aa genotype from Helen and Harry respectively, came together, no homozygous dominant offspring can be produced. This tells us that Hayden must be a heterozygous dominant.

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1 year ago
The diagram below shows the layers in a rock having a brachiopod: A rock column labeled Rock is shown. The column has three laye
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A Xw+m+Xwm female was mated to a XwmY male. Out of 1000 total F1 progeny there were 230 flies that were otherwise wild type with
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In order to calculate the distance between two alleles/genes that are found in the same chromosome, we need to know how often crossing-over happened (recombination frequency). We know from the text that white eyes were linked to miniature wings and that wild type eyes were linked to wild type wings, so any phenotype that's contrary to these parent combinations are a result of crossing-over. We know then that 230 flies + 240 flies were a result of such recombination. To calculate the recombination frequency we only need to divide these flies (total of recombinant flies) by the total of flies in the offspring and turn it into percentage.
\frac{230+240}{1000}=0.47
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47 map units is the distance between the genes <span>for eye color and wing length.</span>
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How is a warm front different from a cold front?
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Warm fronts often bring stormy weather as the warm air mass at the surface rises above the cool air mass, making clouds and storms. Warm fronts move more slowly than cold fronts because it is more difficult for the warm air to push the cold, dense air across the Earth's surface.
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Which of the following best describes a controlled experiment? a. An experiment repeated many times to ensure that the results a
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Answer:

I think the answer is C: An experiment that includes one group for which the scientist controls all variables

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