The correct option are as follows:
estimating temperature to the nearest tenth of a degree
estimating the mass of the sample to the nearest tenth of a gram
the position of the cups of sand and water under the heat lamp
<u>Explanation:</u>
Error is an uncertainty or the amount of deviation in a physical quantity. There may arise some deviance while measuring physical quantity due to approximation.
Instrumental, environmental, procedural, and human are some of the common sources of error. The error can be classified into two types:
i) Random error
ii) Systematic error
Types of error are determined based on the deviation in the result. While observing the temperature of something, the temperature should be noted to the nearest tenth of a degree. In similar way, the mass of the sample should be estimated to the nearest tenth of a gram.
Answer:
Different mass
Different volume
Same density
Explanation:
Intensive physical properties are those properties of a substance that is not dependent on amount i.e. do not change in response to changes in the amount of the substance. Intensive properties include density, temperature, boiling point etc.
On the other hand, extensive properties are those properties that are dependent on the amount of the substance. For example, mass and volume are extensive properties.
Hence, according to this question, measuring an entire bar of soap and comparing it to a piece of soap, the bar and the piece would have a:
- Different mass ( size dependent)
- Different volume (size dependent)
- Same density (size independent)
Solute potential of a solution is calculated using the formula,
Ψ
Where,
Ψ
is the solute potential of the solution,
<em>i</em> is the degree to which the solute ionizes(ionization constant) in solution = 1, as sucrose is a nonelectrolyte.
C is the concentration of the solution in molarity = 0.5 M
R is the gas constant or the pressure constant = 0.0831 L.bar/(mol.K)
T is the temperature in Kelvin scale = 
Calculating the solute potential of the surrounding sucrose solution:
Ψ
= -(1 * 0.5 M * (0.0831 L.bar/(mol.K))* 303 K)
= 12.6 bar
Therefore, the solute potential of the surrounding solution is 12.6 bar
This occurred because one phenotype was completely dominant over the other phenotype.
Hope this helped you.
