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SSSSS [86.1K]
2 years ago
13

A cyclist estimates that he will bike 80 miles this week. He actually bikes 75.5 miles. What is the percent error of the cyclist

's estimate? Round the percent to the nearest hundredth if necessary.
Mathematics
2 answers:
vazorg [7]2 years ago
4 0

Answer:

6%

Step-by-step explanation:

Estimated distance = 80 miles

Actual distance covered = 75.5 miles

We need to find the percent error of the cyclist's estimate. Its formula is given by :

\%=\dfrac{|\text{actual value-estimated value}|}{\text{actual value}}\times 100

Put all the values,

\%=\dfrac{80-75.5}{75.5}\times 100\\\\=5.96\%

or

= 6%

So, the percentage error is 6%.

dalvyx [7]2 years ago
3 0

Answer:

5.96

Step-by-step explanation:

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 [5 x -3]
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Identify the 12th term of the geometric sequence in which a2 = −6 and a6 = −96
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The first-, second-, and third-year enrollment values for a technical school are shown in the table below.
VARVARA [1.3K]

Answer:

The solution to f(x) = t(x) is x = 2010

Option 3 is true.

Step-by-step explanation:

The first-year , second-year , and third-year enrollment values for a technical school are shown in the table below.

Year (x)      First Year f(x)      Second Year s(x)       Third Year t(x)

 2009              785                        756                           756

 2010               740                        785                           740

 2011                690                        710                            781

 2012               732                        732                            710

 2013                781                        755                            800

Now we will check each option.

Option 1: The solution to f(x) = s(x) is x = 2,009

In year 2009, f(x)=s(x)

But 785≠756

Thus, False

Option 2: The solution to f(x) = s(x) is x = 785

x represents year, but 785 it no year

Thus, False

Option 3: The solution to f(x) = t(x) is x = 2010

In year 2010, f(x)=t(x)=740

But 740=740

Thus, True

Option 4: The solution to f(x) = t(x) is x =740

x represents year, but 740 it no year

Thus, False

8 0
2 years ago
The daily energy requirement, E (kilojoules), for a person of mass m ( kilograms) is calculated using the rule E=9m+8100
Wewaii [24]
For this case we have the following equation:
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8 0
2 years ago
An isosceles triangle ABC with the base BC is inscribed in a circle. Find the measure of angles of it, if measure of arc BC = 10
Usimov [2.4K]

Answer:

The measures of the angles of the triangle are 51° , 64.5° , 64.5°

OR

The measures of the angles of the triangle are 129° , 25.5° , 25.5°

Step-by-step explanation:

* Lets explain the meaning of the inscribed triangle in a circle

- If a triangle inscribed in a circle, then the vertices of the triangle lie

 on the circumference of the circle and each vertex is an inscribed

 angle in the circle subtended by the opposite arc

- Fact in the circle the measure of the inscribed angle is 1/2 the

 measure of its subtended arc

* Now lets solve the problem

- Δ ABC is an isosceles with the base BC

∴ AB = AC

∴ m∠B = m∠C

- Δ ABC is inscribed in a circle

∴ ∠A is inscribed angle subtended by arc BC (minor or major)

# The measure of the minor arc is less than 180° and the measure of

  the major arc is greater then 180° and the sum of the two arcs

  equals the measure of the circle which is 360°

∴ ∠B subtended by arc AC

∴ ∠C subtended by arc AB

∵ The measure of the arc BC = 102°

- There is two cases in this question

(1) If the angle A subtended by the minor arc BC

(2) If the angle A subtended by the major arc BC

- Lets solve case (1)

∵ ∠A is an inscribed angle subtended by the minor arc BC

∴ m∠A = 1/2 the measure of the arc BC

∵ The measure of the arc BC is 102°

∴ m∠A = 1/2 × 102 = 51°

∵ The sum of the measures of the interior angles of a triangle is 180°

∴ m∠A + m∠B + m∠C = 180°

∴ 51 + m∠B + m∠C = 180° ⇒ subtract 51 from both sides

∴ m∠B + m∠C = 129°

∵ m∠B = m∠C ⇒ isosceles Δ

∴ m∠B = m∠C = 129/2 = 64.5°

* The measures of the angles of the triangle are 51° , 64.5° , 64.5°

- Lets solve case (2)

∵ ∠A is an inscribed angle subtended by the major arc BC

∴ m∠A = 1/2 the measure of the arc BC

∵ The measure of the minor arc BC is 102°

∵ The measure of the circle is 360°

∴ The measure of the major arc = 360 - 102 = 258°

∴ m∠A = 1/2 × 258 = 129°

∵ The sum of the measures of the interior angles of a triangle is 180°

∴ m∠A + m∠B + m∠C = 180°

∴ 129 + m∠B + m∠C = 180° ⇒ subtract 129 from both sides

∴ m∠B + m∠C = 51°

∵ m∠B = m∠C ⇒ isosceles Δ

∴ m∠B = m∠C = 51/2 = 25.5°

* The measures of the angles of the triangle are 129° , 25.5° , 25.5°

4 0
2 years ago
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