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sweet-ann [11.9K]
2 years ago
13

Both SAR and EC are important attributes of irrigation water. What do these measures indicate? What is the danger of irrigation

with water of:
a. high SAR
b. a high EC?
Business
1 answer:
PSYCHO15rus [73]2 years ago
4 0

Answer:

a. SAR is the Sodium adsorption ratio of the water used for irrigation purpose. SAR is ratio of sodium concentration to that of calcium and magnesium concentration.This value is also useful while managing soils that have high concentration of sodium which can occur naturally in some soils.  Although sodium is a macro-nutrient for plants, higher concentration of sodium can cause the displacement of the calcium and magnesium ions in soil which can affect the soil structure by preventing aggregation of clay in the soil resulting in a decrease in the infiltration rates.

b. EC is the electrical conductivity of the soil which depends on the salinity of the soil. High salinity means more solutes in water and this increases the osmotic potential of the soil solution making it difficult for plants to absorb water.

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Pollyanna Publishing, a textbook publishing firm, purchased a new machine for $80,000. This machine is expected to operate for 1
emmainna [20.7K]

Answer:

A.

The first year’s Depreciation Expense: $14,400

The second year’s depreciation expense: $11,520

B.

The first year’s Depreciation Expense = The second year’s depreciation expense = $7,200

Explanation:

A. Under the straight-line method, useful life is 10 years, so the asset's annual depreciation will be 10% of the Depreciable cost.

Depreciable cost = Total asset cost - salvage value =  $80,000-$8,000 = $72,000

Under the double-declining-balance method the 10% straight line rate is doubled to 20% - multiplied times the Depreciable cost's book value at the beginning of the year.

In the first year, depreciation expense = 20% x $72,000  = $14,400

At the beginning of the second year, the Depreciable cost's book value is $72,000 -$14,400 = $57,600

In the second year, depreciation expense = 20% x $57,600  = $11,520

B.

The company uses straight-line depreciation, Depreciation Expense each year is calculated by following formula:  

Depreciation Expense = (Cost of machine − salvage value)/Useful Life = ($80,000-$8,000)/10 = $7,200

The first year’s Depreciation Expense = The second year’s depreciation expense = $7,200

7 0
2 years ago
________ distribution is a strategy in which producers of convenience prodcuts and raw material stock their products in as many
dem82 [27]

Answer:

Intensive Distribution

Explanation:

Intensive distribution is a strategy in which producers of convenience products and raw material stock their products in as many outlets as possible.

In this strategy, the producers of convenience products try to provide the product to the consumers where and when they want. In this way, consumers get brand exposure for any product they wish to buy and also it made convenient for them to buy the product. Example of such products are soaps, biscuits etc.

Thus the answer for the question is Intensive Distribution.

5 0
2 years ago
Read 2 more answers
The addition of acceptance criteria factors to the milestone schedule in a project charter helps the team understand who will ju
Aleksandr-060686 [28]

Answer:

Standards or criteria that will be used

Explanation:

A project charter is an informal contract between a project team and the project sponsor. The project charter shows a detailed plan of each aspect of a project; from scope to objectives, etc as well as grants the project team the power to create a project plan.

A project charter helps the project team to develop an understanding of the project to be undertaken, thereby enhancing team performance. Before a project charter is signed between both parties, all risks must have been eliminated.

When acceptance criteria factors are added to the schedule of a project charter, it helps the project team to know who will be judging the quality of their work as well as the standard that the judge will be using.

I hope this helps.

3 0
2 years ago
A well-known industrial firm has issued $1,000 bonds that carry a 4% coupon interest rate paid semiannually. The bonds mature 20
Flauer [41]

Answer:

5.59%

Explanation:

$1,000 bonds carrying a 4% coupon rate, semiannual coupon $20, matures in 20 years

if you purchase the bonds at $715, the nominal annual rate of return = coupon payments / bond price = ($20 + $20) / $715 = $40 / $715 = 5.59%

The nominal annual rate of return is calculated by dividing the revenue generated by an investment by the cost of the investment.

8 0
2 years ago
A company is selling bonds with a face value of $1,000 to raise money for a plant expansion. The bonds pay a coupon rate of 4% p
Ksivusya [100]

Answer:

10.26%

Explanation:

According to the scenario, computation of the given data are as follow:-

Net sales = $760

Face value of bonds = $1,000

Coupon rate = 4% = $1,000 × 4 ÷ 100

= 40

N = Number of Years = 5 annually = semiannually = 5 × 2

= 10 years

We assume, interest rate = 10% = 0.10

P = Coupon Rate ÷ 2 × (PVIFA,Interest Rate ÷ 2%,No. of Years) + Future Value(PVIF,Interest Rate ÷ 2%, No. of Years)

=$40 ÷ 2 × [1 - 1 ÷ (1 + Interest Rate)N] ÷ Interest Rate + Future Value[1 ÷ (1 + Interest Rate) × N]

=$40 ÷ 2 × [1-1 ÷ (1 + 0.10 ÷ 2)^10] ÷ 0.05 + $1,000 × [1 ÷ (1 + 0.10 ÷ 2)^10]

=$20 × [1 - 1 ÷ (1.05)^10] ÷ 0.05 + $1,000 × [1 ÷ (1.05)^10]

=$20 × [1 -1 ÷ 1.6288946] ÷ 0.05 + $1,000 × [1 ÷ 1.6288946]

= 420 × 7.72173 + $1,000 × 0.613913

= $154.4346 + $613.913

= $768.3476

= $768.35

But the given value is 760, so we assume interest rate = 11%

=$40 ÷ 2 × [1-1 ÷ (1 + Interest Rate)^N] ÷ Interest Rate + Future Value[1 ÷ (1 + Interest Rate)^N]

= $40 ÷ 2 × [1 - 1 ÷(1 + 0.11 ÷ 2)^10] ÷ 0.055 + $1,000 × [1 ÷ (1 + 0.11 ÷ 2)^10]

= $20 × [1 - 1 ÷ (1.055)^10] ÷ 0.055 + $1,000 × [1 ÷ (1.055)^10]

= $20 × [1 - 1 ÷ 1.70814446] ÷ 0.055 + $1000 × [1 ÷ 1.70814446]

= $20 × 7.5376255 + $1,000 × 0.5854306

= $150.75 + $585.43

= $736.18

At the Interest rate of 10% the price is more than $760 and at the Interest rate of 1% the price is less than $760. So the required rate lies in between 10% to 11%.

So required rate  

Yield To Maturity = Lower Interest Rate + (Difference Between Interest Rate) × Higher Price - Received Price ÷ Higher Price - Lower Price

= 1 0+( 11 - 10) × $768.35 - $760 ÷ $768.35 - $736.18

= 10 + 1 × $8.35 ÷ $32.17

= 10 + 0.26

= 10.26%

7 0
2 years ago
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