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2 years ago

What is the decimal multiplier to decrease by 0.6%?

Mathematics

1 answer:

Zielflug [23.3K]2 years ago

6 0

Step-by-step explanation:

0.6/100= 0.006 should be multiplied to decrease by 0.6%

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From your home the route to the store that passes the beach is 2 miles shorter than the route to the store that passes the park.

Leviafan [203]

House to beach + beach to store = house to park + park to store - 2 (x + 2) + (2x + 2) = (4x) + (x) - 2 3x + 4 = 5x - 2 3x + 6 = 5x 6 = 2x x = 3 Check this: (3 + 2) + (2[3] + 2) = (4[3]) + (3) - 2 5 + 8 = 12 + 3 - 2 13 = 13 So the route from home to the beach and the beach to the store is 13 miles, and the route from home to the park and from the park to the store is 15 miles.

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2 years ago

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Which one of these scales is equivalent to the scale 1 cm to 5 km? 3 cm to 15 km 1 mm to 150 km 5 cm to 2.5 km 1 mm to 500 m

Jobisdone [24]

1cm×3 to 5km×3=3cm to15km

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2 years ago

A painter is painting a wall with an area of 150 ft2. He decides to paint half of the wall and then take a break. After his brea

kotegsom [21]

145.31 ft2 will be painted on his fifth break.

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2 years ago

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udin memiliki 3 ember berisi ikan hias setiap ember berisi 320 ekor berapa banyak ikan hias udin semuanya

Rom4ik [11]

Answer:

960

Step-by-step explanation:

3 * 320 = 960

Udin memiliki, secara total, 960 ikan hias

(Udin has, in total, 960 ornamental fish)

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2 years ago

Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:

Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. $\lim_{n \to \infty} a_n =A$ it must hold that for any small $\epsilon$ >0, there must exist $n_0\in \mathbb{N}$ so that starting from that term of the series all of the following terms satisfy that $|a_n-A|n_0$ .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with $a_n=1$ , the other is constant with $a_n=3$ , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

$a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}$

If we denote the first series as $b_n=1$ , we will have that $\lim_{k \to \infty} b_k=1$ .

The second series is denoted as $c_k=2^k$ and we have that $\lim_{k \to \infty} c_k=+\infty$ .

The third sub-series $d_k=3$ is a constant series and it holds that $\lim_{k \to \infty} d_k=3$ .

Since those limits of sub-series are different, we can never find such $n_0\\$ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose $\epsilon =1$ , all those terms associated with the third sub-series will be out of this interval $(A-1, A+1)=(0, 2)$ .

Therefore, the observed series diverges.

5 0

2 years ago