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Kitty [74]
2 years ago
9

Dave walked to his friend's house at a rate of 4mph and returned back biking at a rate of 10mph. If it took him 18 minutes longe

r to walk than to bike, what was the total distance of the round trip
Mathematics
1 answer:
schepotkina [342]2 years ago
4 0

Answer:

4 miles

Step-by-step explanation:

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In the diagram shown of circle A, segments UV and UT are congruent. If
grandymaker [24]

Answer:

 35°

Step-by-step explanation:

We assume that points S, T, U, V all lie on the circle.

Inscribed angle TUV intercepts long arc VST and short arc VUT. The long arc has measure 220°, so the measure of the short arc is 360° -220° = 140°.

Since chords UV and UT are the same length, point U bisects arc VUT. That means the measure of arc VU is 140°/2 = 70°.

Inscribed angle VSU intercepts arc VU, so has half the measure of the arc:

 ∠VSU = 70°/2

 ∠VSU = 35°

Read more on Brainly.com - brainly.com/question/15559971#readmore

8 0
2 years ago
Tom has $10 that he wants to use to buy pens and pencils. However, he does not want to buy more pens than pencils. A pen costs $
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If he buys x pens and y pencils

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x ≤ y

You draw the line 3x + y = 10 .<span>(it passes by (0,10) and (-10/3,0)

</span>
<span>You Draw the line y=x [it passes by (0,0), (1,1), (2,2)]

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6 0
2 years ago
Read 2 more answers
Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road-oriented at an angle of 25
kap26 [50]

Answer:

6.31 mi

Step-by-step explanation:

The diagram below explains the solution better.

From the diagram,

C = starting point of the race.

A = end of the first part of the race.

B = end of the race.

Using Cosine rule, we can find the straight-line distance between the starting point and the end of the race.

Cosine rule states that:

a^2 = b^2 + c^2 - 2bc[cos(A)]

where A = angle A = <A

Given that

b = 5.2 miles

c = 2.0 miles

<A = 115° (from the diagram)

Hence,

a^2 = 5.2^2 + 2.0^2 - 2*5.2*2.0[cos(115)]\\\\a^2 = 27.04 + 4 - 20.8[cos(115)]\\\\a^2 = 31.04 + 8.79\\\\a^2 = 39.83\\\\a = \sqrt{39.83}\\ \\a = 6.31 mi

The straight-line distance between the starting point and the end of the race is 6.31 mi

4 0
2 years ago
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