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liq [111]
2 years ago
3

Colin buys a tv for £800. It depreciates at a rate of 1% per year. How much will it be worth in 2 years? Give your answer to the

nearest penny where appropriate
Mathematics
1 answer:
sweet [91]2 years ago
3 0

Answer:

708

Step-by-step explanation:

Answer

1.7/5

1

bhagyashreechowdhury

Ace

2.4K answers

4.9M people helped

Given:

The cost of the T.V. for Colin = £ 800.

The rate of depreciation per year = 4%

Time period = 3 years

To find:

How much will it be worth in 3 years? Give your answer to the nearest penny where appropriate.

Solution:

To solve the above-given problem, we will use the following formula:

where

A = the final value after depreciation

P = the present value

R = rate of depreciation

n = time period

Now, on substituting the given values in the formula, we get

we will round the above answer to its nearest penny where appropriate

≈ £ 708

Thus, the worth of the t.v. in 3 years will be £ 708.

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4 0
2 years ago
a previous analysis of paper boxes showed that the standard deviation of their lengths is 15 millimeters. A packers wishes to fi
vladimir1956 [14]

Answer:

864.36 boxes

Step-by-step explanation:

In the question above, we are given the following values,

Confidence interval 95%

Since we know the confidence interval, we can find the score.

Z score = 1.96

σ , Standards deviation = 15mm

Margin of error = 1 mm

The formula to use to solve the above question is given as:

No of boxes =[ (z score × standard deviation)/ margin of error]²

No of boxes = [(1.96 × 15)/1]²

= 864.36 boxes

Based on the options above, we can round it up to 97 boxes.

8 0
2 years ago
a school baseball team raised $810 for new uniforms. each player on the team sold one book of tickets. There were 10 tickers in
Orlov [11]
1 Book = $30
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4 0
2 years ago
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Below are boxplots that summarize the weights (in pounds) of large samples from two breeds of dog: the Anatolian Shepherd and th
koban [17]

Answer:

(a) The median of both plots is same, 120 pounds is the median weight of Anatolian Shepherd and the Black Russian Terrier breed.

The range of both plots is also same that is 75 pounds.

The box plot of Anatolian Shepherd is skewed towards left therefore, it is considered to be positively distributed.

The box plot of Black Russian Terrier is skewed towards right therefore, it is considered to be negatively

(b) Any data point which is greater than 155 or smaller than 80 will be considered an outlier.

Step-by-step explanation:

A box plot is a graph which shows five statistical characteristics of a data set.

1. Maximum value

2. Minimum value

3. Median

4. Upper Interquartile

5. Lower interquartile

(a) Compare the distributions of weights for the two dog breeds

Please refer to the attached diagram of the question.

The median of both plots is same, 120 pounds is the median weight of Anatolian Shepherd and the Black Russian Terrier breed.

The range of Anatolian Shepherd is,

Range = Maximum value - Minimum value

Range = 175 - 100 = 75 pounds

The range of Black Russian Terrier is,

Range = Maximum value - Minimum value

Range = 155 - 80 = 75 pounds

Therefore, the range of both plots is also same that is 75 pounds.

A box-plot is considered to be normally distributed when the median is at the center of upper quartile and lower quartile.

The box plot of Anatolian Shepherd is skewed towards left therefore, it is considered to be positively distributed.

The box plot of Black Russian Terrier is skewed towards right therefore, it is considered to be negatively distributed.

(b) What weights would a Black Russian Terrier have to be to be considered an outlier?

An outlier is a data point in the data set that is very different from the other data points.

In this case, the maximum and minimum values in the Black Russian Terrier box-plot are

Maximum = 155

Minimum = 80

Therefore, any data point which is greater than 155 or smaller than 80 will be considered an outlier.

5 0
2 years ago
julie jot 21 of the 23 questions of her math test correct she got 29 of the 32 questions on her science test correct on which te
Alenkasestr [34]
Make\ a\ common\ denominator:\\\\\frac{21}{23}\ \ \ \ \ \ \ \ \frac{29}{32}\\\\\frac{21\cdot32}{23\cdot32}\ \ \ \ \ \ \ \frac{29\cdot23}{32\cdot23}\\\\\frac{672}{736}\ \ \ > \ \ \ \frac{667}{736}
5 0
2 years ago
Read 2 more answers
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