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2 years ago

Different parts of the human digestive system help to break down molecules of fat so

Biology

1 answer:

slavikrds [6]2 years ago

5 0

Answer:

Small intestine, liver, bile and lipase.

Explanation:

Digestion of fat occurs in the small intestine. Its digestion occurs with the help of bile, that is made in the liver. Bile breaks the fat into small drops that are easier for the lipase enzymes to change it. Lipase enzymes is a type of enzymes that works only on lipids and lipids are broken down into fatty acids and glycerol. These substances are absorbed by our body and used it for producing ATP for the body.

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Based on the results above, you study the settlement patterns of the three species. You establish transects on each of your expe

dem82 [27]

Answer:

c. Physical adaptations to the environment drive the distribution of all three species in the wild.

Explanation:

Options A and B refer to competition between species. The experiment was about the colonizing ability of the three species, and not the interaction among them. So these two options are not correct.

Option D states that species A is better adapted to the upper intertidal zone than the middle or lower. But the table shows that species A is equally adapted to colonize upper and middle intertidal zone, and less adapted to colonize lower zones.

The correct option is C. When these competing species coexist, this is because of niche partitioning or niche differentiation. If there is not any differentiation between them, the dominant species displaces the weak species. In the exposed example, the three species coexist in the middle and lower zones, which means that they probably have different niches and got adapted to living to their environments. This adaptation to different conditions is what leads to their distribution.

In the exposed example, species A and B can live in the upper intertidal zone, where species C can not live because they can not tolerate environmental conditions. The three species can live in the middle zone, but still, A and B are more adapted to this area than C. Among A and B, B is the most adapted to living in the upper and middle zones. Species C seems to be very adapted to live in the lower intertidal zone, where species A and B can also live, but are less adapted to this area, probably due to environmental conditions or due to their vulnerability to predation. In this last area, species A is less adapted.

3 0

2 years ago

Oh, no... you dropped your study flashcards, and now they're out of order! Put them back into the correct order for a eukaryotic

Nezavi [6.7K]

The given question is incomplete, the complete question is:

Oh, no... you dropped your study flashcards, and now they're out of order! Put them back into the correct order for a eukaryotic cell.

a. "Combine the mRNA strand with a ribosome and a tRNA carrying a methionine."

b. "Unwind the DNA molecule near the promoter."

c. "Exit the nucleus to the cytoplasm."

d. "Transcribe the complementary RNA strand."

[Tip: you might want to work out the correct order on a piece of scratch paper before selecting from the options below.]

c - d - b - a

b - d - c - a

c - b - d - a

d - b - c - a

b - d - a - c

Answer:

The correct order would be b, d, c, a.

Explanation:

First unwinding of the molecule of DNA takes place close to the promoter. After that transcription of the complementary RNA strand takes place, then mRNA moves out of the nucleus into the cytoplasm. Ultimately, the combination of ribosome and tRNA carrying a methionine takes place with the mRNA.

The order is based upon the central dogma of the cell. Based on the central dogma concept, the transcription of the mRNA takes place in the first place, which then gets transported out of the nucleus into the cytoplasm in the eukaryotic cell. The unwinding of DNA takes place close to the sequence of the promoter for the process of transcription.

In the promoter region, various transcription factors are present and binding of RNA polymerase takes place with the template strand. The generated mRNA then get transported out of the nucleus into the cytoplasm. Post transcription, translation of mRNA takes place with the assistance of tRNA and ribosome. In the mRNA, the start codon generally codes for methionine because of which the tRNA that carries methionine identifies the start codon, and the process of translation gets initiated.

5 0

2 years ago

student prepared a test tube containing yeast, glucose, and water. After 24 hours, the test tube was analyzed for the presence o

expeople1 [14]

Answer:

In the presence of oxygen, respiration of yeast produces carbon dioxide and water. In the absence of oxygen, respiration of yeast produces carbon dioxide and alcohol.

Under the assumption that the yeast has insufficient exposure to oxygen in the surrounding air in the testtube, alcohol and carbon dioxide would be expected to be found in the test tube

5 0

2 years ago

You decide to refresh your memory about each of the disorders mentioned by your attending. A good source of medical information

lakkis [162]

Answer:

its a

Explanation:

7 0

2 years ago

Read 2 more answers

2. As a result of your initial efforts you were able to detect the presence of protein K using IgG. However, when your lab mate

Viefleur [7K]

Answer:

Protein K is a protein that can available in the human cell nucleus that binds to pre-messenger RNA as a part of heterogenous ribonucleoprotein. IgG is one of the five isotypes of immunoglobulin or antibodies.it is the most common antibodies in the blood circulation and makes the 75% of total antibody.

When you heat solution, generally protein k activity increase with an increase in the heat but up to an extent or point called optimum temp. The optimal temperature for activity ranges between 50-65°c. When an increase in temperature help with protein unfolding easing the ability for protein k to break down those proteins.

8 0

2 years ago