One of the genes that controls color vision is found on the X chromosome. The dominant allele results in normal color vision, an
2 answers:
Answer:
1/4
Explanation:
The trait is X-linked and recessive. A male only need one recessive allele to be affected while a female needs 2 recessive alleles to be affected.
Let the color vision allele be C.
Ginny is heterozygous, her genotype will be
Harry is color blind, his genotype will be
If Ginny and Harry mate, their offspring's genotype will be:
is a heterozygous female with normal vision
normal vision male
color blind female
color blind male
Probability of having a color blind child = 1/2
Probability of having a son = 1/2
Probability of having a colorblind son = probability of having a colorblind child and probability of the child being a son
= 1/2 x 1/2
= 1/4
The probability of at least one of the children being a colorblind son is 1/4
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Answer:
Explanation:
<em>The probability of producing plants with white axial flowers would be 1/16.</em>
From the illustration, All F1 individuals had red, axial flowers. It thus means that red and axial genes are dominant over white and terminal genes in the pea plant.
Let us assume that the allele for flower color is A (red) and a (white); and the allele for flower location is B (axial) and b (terminal).
Pure-breeding red, axial flower = AABB
Pure breeding white, terminal flower = aabb
AABB x aabb
F1 genotype = AaBb - all red and axial
At F2:
AaBb x AaBb
Progeny
<em>9 A_B_ red/axial</em>
<em>3 A_bb red/terminal</em>
<em>3 aaB_ white/axial</em>
<em>1 aabb - white/terminal</em>
Hence, the probability of producing plants with white axial flowers in the F2 generation is 1/16.
