Question

Two true-breeding stocks of pea plants are crossed. One parent has red, axial flowers, and the other has white, terminal flowers. All F1 individuals have red, axial flowers. (Note which alleles are dominant/recessive.) The genes for flower color (red/white) and flower location (axial/terminal) assort independently. According to a traditional Mendel experiment, what is the probability of producing plants with white axial flowers in the F2 generation?

Answer 1

Answer:

Explanation:

The probability of producing plants with white axial flowers would be 1/16.

From the illustration, All F1 individuals had red, axial flowers. It thus means that red and axial genes are dominant over white and terminal genes in the pea plant.

Let us assume that the allele for flower color is A (red) and a (white); and the allele for flower location is B (axial) and b (terminal).

Pure-breeding red, axial flower = AABB

Pure breeding white, terminal flower = aabb

AABB   x    aabb

F1 genotype = AaBb - all red and axial

At F2:

AaBb   x   AaBb

Progeny

9 A_B_ red/axial

3 A_bb red/terminal

3 aaB_ white/axial

1 aabb - white/terminal

Hence, the probability of producing plants with white axial flowers in the F2 generation is 1/16.