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Answer:A. the same number of chromosomes as was contained in the zygote.
Explanation:a zygote is formed when the sperm fertilize the egg .
After fertilization,the zygote undergoes cleavage.cleavage is the mitotic Division of the cells of a zygote to produce daughter cells.
These daughter cells are called blastomere,which contains the same number of chromosomes as the parent cells.the cells formed do not grow in size but continues to divide, forming a mass of cells.
This mass may be solid at first but as cleavage continues,the cells move away from the center,leaving a fluid filled cavity in the middle (blastocoel).
The mass of cells are called blastula.
Answer:
Consider the heterozygous oval, thick cell walled bacteria to have the alleles OoTT and the thin cell walled bacteria to have alleles oott. Results will be 50% oval, thick walled bacteria and 50% round, thick walled bacteria. This will be the F1 progeny.
When the oval, thick walled bacteria from the F1 progeny is cross bred with round, thick walled bacteria then 25 percent of the bacteria will be heterozygous oval, thick walled. 25 percent will be heterozygous oval and heterozygous thick walled. 25 percent will be round and thick walled. 25 percent will be round and thin walled.
The majority of water molecules moving across plasma membranes by osmosis do so via a process that is most similar to simple diffusion. The process of osmosis involves the moment of water molecules across a semipermeable membrane like the cell membrane from a region of high water concentration to a region of low water concentration. This process is similar to the process of simple diffusion where the solute particles move across in a similar fashion.
Answer:
Frequency of the B3 allele 
Explanation:
The allele frequencies in a given population remain constant which means that every generation will have the same gene pool across the generations. As per Hardy Weinberg’s first equilibrium equation, the sum of frequency of all the alleles at a given locus is equal to one
Thus, if "p" represents the frequency of B1 allele and "q" represents the frequency of B2 allele and "r" represents the allele for B3 allele. Then, sum or "p", "q" and "r" is equal to one.

Substituting the given values, we get -
