Answer:
Option D, 75%
Explanation:
Let the genotype of co dominant checkered hen mates and checkered rooster be CcC and CcC
Where Cc – is the allele for chekered skin
C – is the allele for non chekered skin
Co-dominant allele are those which irrespective of being dominant or recessive are expressed equally.
The punnet square for the cross between these two would be
Cc C
Cc CcCc CcC
C CCc CC
3 out of 4 offsprings have chekered allele i.e CcCc, CcC and CcC. Thus, the probability of chekered offsprings would be 75%
I assume that in this item, we are asked to solve for the force exerted during the heartbeat. Force is the product of the mass and acceleration. To solve for the acceleration in this item, we divide the velocity by time.
a = 1 m/s / 0.2 s = 5 m/s²
Then, we multiply this by the mass (in kg)
F = (80 g / 1000 g/kg) x (5 m/s²)
= 0.4 kg m/s² = 0.4 J
Therefore, every hearbeat will take 0.4 J of force.
Answer:
The correct answer is - damaged, effector organ, neurilemma, damage, distance, cell body, decreased.
Explanation:
PNS axons are prone to cuts, and other types of injuries. A damaged axon can regenerate if the effector organ remains intact and a critical amount of neurilemma is found.
The degree of success of these axons regeneration depends upon factors that are (1) the amount of damage, and (2) the distance between the site of the damaged axon and the cell body it innervates The possibility of repair is reduced with an increase in either of these two factors. Neurolemmocytes play an active role in regeneration
In order to calculate the distance between two alleles/genes that are found in the same chromosome, we need to know how often crossing-over happened (recombination frequency). We know from the text that white eyes were linked to miniature wings and that wild type eyes were linked to wild type wings, so any phenotype that's contrary to these parent combinations are a result of crossing-over. We know then that 230 flies + 240 flies were a result of such recombination. To calculate the recombination frequency we only need to divide these flies (total of recombinant flies) by the total of flies in the offspring and turn it into percentage.
=0.47
0.47*100%=47%
47 map units is the distance between the genes <span>for eye color and wing length.</span>
Answer:
1.) neurilemma (option f)
2.) nissil bodies (chromatiophillic substance)
3.) neurofibrilis ( option g)
4.) myelin ( option e)
5.) dendrite ( option d)
6.) collateral ( option c)
7.) astrocytes (option a)
8.) axon ( option b)
9.) Unipolar neuron (option i)
Explanation:
The neurological terms described above are different parts of a nerve cell or neurones. The nerve cells are the basic Structural units of the nervous system. They are highly specialised for transmitting electric impulses. They can also be grouped according to the number of processes they possess, for example, the UNIPOLAR NEURONS( those with one process only). Each neuron, however, is composed of the same basic parts which include:
--> The CELL BODY: they may be angular or oval in shape with a large nucleus and dense granulated cytoplasm. In the cytoplasm, rough Endoplasmic reticulum which contains CHROMATIOPHILLIC SUBSTANCE (nissil bodies) and Golgi apparatus are also seen.Network of threadlike structures known as neurofibrilis are also seen within the cell body and extending into axon.
--> DENDRONS: these are one or more extensions which branches to form many fine dendrites. The DENDRONS carry nerve impulses( action potential) that their dendrites receive to the cell body.
--> AXON: this is a long process which branches at it's free end to end in synaptic knobs. It carries electric impulses away from the cell body. Most times, a substance of Schwann cell known as MYELIN SHEATH which is composed of lipoprotein insulates axons and increases impulse speed.
