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ZanzabumX [31]
1 year ago
3

(20 POINTS!! HELP ASAP) Use the image above to identify and explain the relationship between the segments and circles A and B. I

n your explanation, be sure to include specific vocabulary and definitions for the relationships.
CD

Mathematics
2 answers:
Pavlova-9 [17]1 year ago
4 0

Answer:

Step-by-step explanation:

ER is tangent to circle A and B , CD is tangent to circle B PQ is a arc in circle A

rCRS is an arc in circle B. And lastly Ps is also tangent to both circles.

Fantom [35]1 year ago
4 0

Answer:

ER is tangent to circle A and B , CD is tangent to circle B PQ is a arc in circle A

rCRS is an arc in circle B. And lastly Ps is also tangent to both circles.

qt is also a tangent to both circles.

Step-by-step explanation:

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A company produces metal slabs for industrial use. the slabs come in 3 thicknesses: 5in, 10in, and 15in. the weights of each thi
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Given slabs thicknesses 5in, 10in, and 15in.

Therefore,<u> </u><u>ratio of thicknesses in simplest form would be 1:2:3.</u>

Metal 1 thicknesses =  150lbs, 300lbs, 600lbs

Dividing by 150, we get ratio of Metal 1 thicknesses = 1:2:4.

Metal 2 thicknesses = 130lbs, 260lbs, 390lbs.

Dividing by 130, we get ratio of Metal 2 thicknesses =  1:2:3.

Metal 3 thicknesses = 310lbs, 620lbs, 930lbs.

Dividing by 310, we get ratio of Metal 3 thicknesses = 1:2:3.

Metal 4 thicknesses = 140lbs, 280lbs, 420lbs.

Dividing by 140, we get ratio of Metal 4 thicknesses = 1:2:3.

<u>We can see the ratios of thicknesses of Metal 1 are 1:2:4 but it should be 1:2:3.</u>

Therefore, Metal 1 weight is not proportional to thickness.


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Jack bought a car for $17,500. The car loses $750 in value each year. Which equation represents the situation? Question 9 option
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A sports company wants to package a ball with a 1.5-inch radius in sets of two. They have two options: a cylinder or a square pr
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Step 1

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we know that

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In this problem we have

r=1.5\ in

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V=\frac{4}{3} \pi 1.5^{3}=4.5\pi\ in^{3}

so

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V=2*4.5\pi=9 \pi\ in^{3}

Step 2

Find the volume of a cylinder

we know that

The Volume of a cylinder is equal to    

V=\pi r^{2}h

In this problem we have

r=1.5\ in

h=4*r=4*1.5=6\ in    

Substitute

V=\pi (1.5^{2})(6)=13.5 \pi\ in^{3}

Step 3

Find the amount of wasted space in the cylinder

Subtract the volume of the two balls from the volume of the cylinder

13.5\pi\ in^{3}-9\pi\ in^{3}=4.5\pi\ in^{3}=14.14\ in^{3}    

Step 4

Find the volume of the square prism

The volume of the prism is equal to

V=Bh

where

B is the area of the base of the prism

h is the height of the prism

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B=(2*1.5)^{2}=9\ in^{2} -----> the base is equal to the diameter    

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V=9*6=54\ in^{3}

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Find the amount of wasted space in the prism

Subtract the volume of the two balls from the volume of the prism

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Step 6

Compare the amount of wasted space

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Find the difference

25.73\ in^{3}-14.14\ in^{3}=11.59\ in^{3}=11.6\ in^{3}

The package that has the least amount of wasted space is the cylinder

therefore

<u>the answer is the option</u>

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Answer:

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Step-by-step explanation:

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