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Viefleur [7K]
2 years ago
10

Hallar el peso molecular de las siguientes sustancias. NaCl HNO 3 KI Na 2 S Ca(OH) 2 H 2 SO 4 KCL CuSO 4 CH 4 LiOH

Law
1 answer:
GrogVix [38]2 years ago
4 0

Answer:

Ver respuesta abajo

Explanation:

Esto es de la asignatura química y no leyes, sin embargo te voy a ayudar con esto.

Para calcular el peso molecular de cualquier sustancia o compuesto, necesitamos los pesos atómicos de los elementos que componen la molécula. Iremos por parte.

Para cada compuesto, escribiremos el peso atómico necesario, y luego calcularemos el peso molecular

<u>a) NaCl</u>

Na: 23 g/mol;  Cl: 35.5 g/mol

PM = 23 + 35.5

PM = 58.5 g/mol

<u>b) HNO₃</u>

H: 1 g/mol; N: 14 g/mol; O = 16 g/mol

PM = 1 + 14 + 3(16)

PM = 63 g/mol

<u>c) KI</u>

K: 39.1 g/mol; I: 126.9 g/mol

PM = 39.1 + 126.9

PM = 166 g/mol

<u>d) Na₂S</u>

Na: 23 g/mol;  S: 32 g/mol

PM = 2(23) + 32

PM = 78 g/mol

<u>e) Ca(OH)₂</u>

Ca: 40 g/mol;  O: 16 g/mol;  H: 1 g/mol

PM = 40 + 2(16) + 2(1)

PM = 75 g/mol

<u>f) H₂SO₄:</u>

H: 1 g/mol;  S = 32 g/mol;  O = 16 g/mol

PM = 2(1) + 32 + 4(16)

PM = 98 g/mol

<u>g) KCl</u>

K: 39 g/mol;  Cl: 35.5 g/mol

PM = 39 + 35.5

PM = 74.5 g/mol

<u>h) CuSO₄</u>

Cu: 63.55 g/mol;  S: 32 g/mol;  O = 16 g/mol

PM = 63.55 + 32 + 4(16)

PM = 159.55 g/mol

<u>i) CH₄</u>

C: 12 g/mol;  H: 1 g/mol

PM = 12 + 4(1)

PM = 16 g/mol

<u>j) LiOH</u>

Li: 6.94 g/mol;  O: 16 g/mol;  H: 1 g/mol

PM = 6.94 + 16 + 1

PM = 23.94 g/mol

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