Find the linear approximation at x=0 to 1/√(3−x). Write your answer in the form y=Ax+B.

1 answer:

4 0

<span>1/root(5-x) = 1/(root5 * root 1- x/5)
1/root5 * (1-x/5)^-1/2

Using the 1st 2 terms of the binomial expansion 1 +nx:
1/root5 ( 1 + x/10)
= X/10root5 + 1/root5</span>

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In measuring reaction time, a psychologist estimates that a standard deviation is .05 seconds. How large a sample of measurement

blondinia [14]

Answer:

Step-by-step explanation:

We are asked to find the size of sample to be 95% confident that the error in psychologist estimate of mean reaction time will not exceed 0.01 seconds.

We will use following formula to solve our given problem.

$n\geq (\frac{z_{\alpha/2}\cdot\sigma}{E})^2$ , where,

$\sigma=\text{Standard deviation}=0.05$ ,

$\alpha=\text{Significance level}=1-0.95=0.05$ ,

$z_{\alpha/2}=\text{Critical value}=z_{0.025}=1.96$ .

$E=\text{Margin of error}$

$n=\text{Sample size}$

Substitute given values:

$n\geq (\frac{z_{0.025}\cdot\sigma}{E})^2$

$n\geq (\frac{1.96\cdot0.05}{0.01})^2$

$n\geq (\frac{0.098}{0.01})^2$

$n\geq (9.8)^2$

$n\geq 96.04$

Therefore, the sample size must be 97 in order to be 95% confident that the error in his estimate of mean reaction time will not exceed 0.01 seconds.

5 0

2 years ago

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a_sh-v [17]

Answer:

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