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Dvinal [7]
2 years ago
5

Which of the following statement is False? 1 point Context free language is the subset of context sensitive language Regular lan

guage is the subset of context sensitive language Recursively enumerable language is the super set of regular language Context sensitive language is a subset of context free language
Computers and Technology
1 answer:
alisha [4.7K]2 years ago
3 0

Answer:

Context-sensitive language is a subset of context-free language

Explanation:

Considering the available options, the statement that is considered wrong is "Context-sensitive language is a subset of context-free language."

This is because generally every regular language can be produced through the means of context-free grammar, while context-free language can be produced through the means of context-sensitive grammar, and at the same time, context-sensitive grammars are produced through the means of Recursively innumerable.

Hence, the correct answer in this correct answer to the question is the last option *Context-sensitive language is a subset of context-free langage

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Answer: im not sure you should just you tube it

Explanation:

You tube can teach you a lot of things you just need to use it

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1 year ago
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Suppose a host has a 1-MB file that is to be sent to another host. The file takes 1 second of CPU time to compress 50%, or 2 sec
kozerog [31]

Answer: bandwidth = 0.10 MB/s

Explanation:

Given

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.50 MB / Bandwidth)

Transfer Size = 0.50 MB

Total Time = Compression Time + RTT + (0.50 MB /Bandwidth)

Total Time = 1 s + RTT + (0.50 MB / Bandwidth)

Compression Time = 1 sec

Situation B:

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.40 MB / Bandwidth)

Transfer Size = 0.40 MB

Total Time = Compression Time + RTT + (0.40 MB /Bandwidth)

Total Time = 2 s + RTT + (0.40 MB / Bandwidth)

Compression Time = 2 sec

Setting the total times equal:

1 s + RTT + (0.50 MB / Bandwidth) = 2 s + RTT + (0.40 MB /Bandwidth)

As the equation is simplified, the RTT term drops out(which will be discussed later):

1 s + (0.50 MB / Bandwidth) = 2 s + (0.40 MB /Bandwidth)

Like terms are collected:

(0.50 MB / Bandwidth) - (0.40 MB / Bandwidth) = 2 s - 1s

0.10 MB / Bandwidth = 1 s

Algebra is applied:

0.10 MB / 1 s = Bandwidth

Simplify:

0.10 MB/s = Bandwidth

The bandwidth, at which the two total times are equivalent, is 0.10 MB/s, or 800 kbps.

(2) . Assume the RTT for the network connection is 200 ms.

For situtation 1:  

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 1 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.50 MB

Total Time = 1.2 sec + 5 sec

Total Time = 6.2 sec

For situation 2:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 2 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.40 MB

Total Time = 2.2 sec + 4 sec

Total Time = 6.2 sec

Thus, latency is not a factor.

5 0
1 year ago
Members of the sales team use laptops to connect to the company network. While traveling, they connect their laptops to the inte
coldgirl [10]

Answer: Network access control (NAC)

Explanation:

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This program finds the sum and average of three numbers. What are the proper codes for Lines a and b?
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Answer:

The Proper codes in Line a and Line b is given below

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Explanation:

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Answer:

Windows\System32\drivers folder

Explanation:

6 0
2 years ago
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